Complete and balance the following half-reactions. In each case indicate whether the half-reaction is an oxidation or a reduction. (g) Cr1OH231s2 ¡ CrO42-1aq2 (basic solution)

Video transcript

everyone in this question asked about the balance have reactions under basic conditions and identify whether it is an oxidation or reduction reaction. Let's write this out at PB two plus hey chris and it's gonna be a P B oh too solid. We need to first balance the non hydrogen and non oxygen elements first and this is already balanced. And now we need to balance the oxygen by adding H 20 liquid to the side that needs oxygen. We have no option on the reactant side but we have to on the product side we can add to H liquid to the reacting side. Now we need to balance the hydrogen by adding H plus to the side that needs hydrogen. Therefore hydrogen on the wrapping side but not on the product side, We can add four h plus for the product side. Now we need to balance the charges by adding the electrons to the more positive side. If you look at our charges, I have zero here plus two here You are here and a plus four here we have overall of plus two over here plus four over here We need to add two electrons to the product side. Now I need to balance our remaining H plus by adding an equal amount of O. H minus ions to both sides. We have four H plus on the product side, we need to add +40 H minus to both sides. But now H plus n O H minus will combine to form H +20 liquid. We're gonna get PB plus last two H 20 liquid Plus 40 H -. Hey chris It's gonna get PB. Colin Plus four H 20. Like wine has two electrons so now we can cancel our common species. We have two H 20 on the wrapping side before on the product side They're gonna be left with 2 H20 on the product side. For the balanced reaction We have PL two plus Plus four H -. And this shows PBO two solid plus two H +20 liquid plus two electrons. And now for the oxidation reaction this means we're losing electrons. So the electrons gonna be on the product side for reduction reaction, we're getting electrons so the electrons going to be on the wrapped inside. So in this case we have oxidation reaction, we're losing electrons. We have electrons on the product side. Thanks for watching my video and I hope it was helpful.