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Ch.20 - Electrochemistry

Chapter 20, Problem 25e

Complete and balance the following equations, and identify the oxidizing and reducing agents: MnO4-1aq2 + Br -1aq2 ¡ MnO21s2 + BrO3-1aq2 (basic solution)

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everyone see her as the balance of following a redox reaction. Under basic conditions and identify the oxidizing and reducing agents. We need to first separate the whole reaction into two half reactions. We're gonna have ZN solid and the show CNN two plus years. We have br or three -A Quiz and it shows be our finest. We need to first balance the non hydrogen and non oxygen elements first and as we can see these are already balanced. So now we need to balance the oxygen by adding H 20 liquid to decide that needs oxygen. If we look at our second reaction we have three options on the rocking side but none on the product side. We can add three H 20 liquid. The product side. Now I need to balance our hydrogen by adding H plus to the side that needs hydrogen. We have six hydrogen on the product side. So we need to add six H plus to the reactant side. Now we can balance our charges by adding electrons to the more positive side. If you look at our charges have zero here plus two here Plus 6 -1 negative on the first reaction you need to add electrons to the product side, We're gonna add two electrons here. From the second reaction we need to add electrons to the reactive side. We're gonna add six electrons And I need to balance the electrons on the 2/2 reactions. There's two electrons in the first reaction and six and the second so we can both talk about three in the first for the oxidation reaction we're losing electrons. So the electrons going to be on the product side for the reduction reaction we're gaining electrons electrons going to be on the reactive side. About oxidation reaction. There's three Zn solid plus three Zn two plus years. Six electrons for reduction half reaction. The B. R of three minus a queens Plus six h plus plus six electrons. And we can't be r minus chris That's three H 20. Like when for our loss of electrons it's an oxidation and it's our reducing agent which is gonna be Zn solid for gain of electrons. This is reduction, it's an oxidizing agent. It's gonna be B R 03 minus a quiz. And I need to balance the remaining H plus, adding an equal amount of which minus ions to both sides. So if we look at the second reaction, you have six H plus. So we need to add +60. H minus to both sides. We're gonna get B R minus B. R. 03 minus chris plus six H plus plus six electrons plus six O. H minus. This is gonna be our minus chris plus three H +20 liquid Plus 60. H - Prius. And the H plus and L. H minus will combine to form H +20 liquid B R three minus quiz. Six nice shoot out liquid plus six electrons. Getting B R minus plus three H + liquid 60. H minus squares. So now I need to cancel a common species. It's gonna be the six electrons And we're also gonna be left with 3 H20 on the reactant side. For our balance redox reaction, We're gonna get three sink solid plus B. R. Of three -A Quiz. That's 3 H20 sequins And then show three I think two plus plus B R minus chris plus it O H minus. Thanks for watching my video and I hope it was helpful.