Skip to main content
Ch.2 - Atoms, Molecules, and Ions

Chapter 2, Problem 81b2

(b) Pentane is the alkane with a chain of five carbon atoms. Determine its molecular formula.

Verified Solution
Video duration:
2m
This video solution was recommended by our tutors as helpful for the problem above.
1035
views
Was this helpful?

Video transcript

hey everyone in this example, we have cyclo hexane, which is a six carbon atom ring. We need to determine the molecular formula for this compound. So drawing out cycle hexane, we have a six carbon ring. So we'll have our first carbon here bonded to a second carbon. We have a third carbon here, 1/4 carbon, 1/5 carbon and then a six carbon which completes our structure. So we can count a total of 12345 and 64 hour cyclo hexane ring. And to complete this molecule, we want to go ahead and recall that for each of our carbon atoms to be stable, they need to be bonded to four atoms Right now this carbon is bonded to two other atoms. However, if we go ahead and include the fact that this carbon is bonded to also to hydrogen which is interpreted in most structures, we would understand that this carbon is stable and that would apply to each of our carbons in this ring. So we can just go ahead and just for clarity, draw in these CH two s and so to get our molecular formula, we're going to count the total number of atoms we have in this molecule right now for our hydrogen is we have two hydrogen is bonded to each carbon atom and so we can count a total of 246, 8, 10, 12 Hydrogen Atoms. And as far as our carbons, we agreed that we have six carbon atoms because we have a ring of six carbons. And so we would say that therefore we have the following molecular formula, which is C six H 12 for cyclo hexane, and this would be our final answer to complete this example. So I hope that everything I explained was clear. This is our molecular formula. And if you have any questions, please leave them down below. Otherwise, I'll see everyone in the next practice video.
Related Practice
Textbook Question

"The diameter of a rubidium atom is 495 pm We will consider two different ways of placing the atoms on a surface. In arrangement A, all the atoms are lined up with one another to form a square grid. Arrangement B is called a close-packed arrangement because the atoms sit in the 'depressions' formed by the previous row of atoms:

(c) If extended to three dimensions, which arrangement would lead to a greater density for Rb metal?"

805
views
Textbook Question

(b) Pentane is the alkane with a chain of five carbon atoms. Determine its empirical formula.

521
views
Textbook Question

Cyclopropane is an interesting hydrocarbon. Instead of having three carbons in a row, the three carbons form a ring, as shown in this perspective drawing (see Figure 2.18 for a prior example of this kind of drawing):

Cyclopropane was at one time used as an anesthetic, but its use was discontinued, in part because it is highly flammable. (a) How does it differ from that of propane?

499
views
Textbook Question

Rubidium has two naturally occurring isotopes, rubidium-85 (atomic mass = 84.9118 amu; abundance = 72.15%) and rubidium-87 (atomic mass = 86.9092 amu; abundance = 27.85%). Calculate the atomic weight of rubidium

6607
views
Textbook Question

A chemist finds that 30.82 g of nitrogen will react with 17.60, 35.20, 70.40, or 88.00 g of oxygen to form four different compounds. (a) Calculate the mass of oxygen per gram of nitrogen in each compound. 30.82 g N and 35.20 g O

504
views
Textbook Question

A chemist finds that 30.82 g of nitrogen will react with 17.60, 35.20, 70.40, or 88.00 g of oxygen to form four different compounds. (a) Calculate the mass of oxygen per gram of nitrogen in each compound. 30.82 g N and 70.40 g O

371
views