Skip to main content
Ch.19 - Chemical Thermodynamics

Chapter 19, Problem 26b

(b) In a particular spontaneous process the entropy of the system decreases. What can you conclude about the sign and magnitude of ΔSsurr?

Verified Solution
Video duration:
56s
This video solution was recommended by our tutors as helpful for the problem above.
406
views
Was this helpful?

Video transcript

Hello. In this problem we are told for non spontaneous process, the change in entropy of the system is negative whereas to identify the sign for the change in entropy of the universe. So the change in HP of the universe is equal to the change in entropy of the system. Plus the change in entropy of the surroundings. If we have a non spontaneous process and the change in entropy of the universe will be negative. We have a spontaneous process. The change in entropy of the universe will be positive. And if we have a reversible process the change in entropy of the universe will be equal to zero. So given that we have a non spontaneous process, that means then the sign for the change in entropy of the universe is going to be negative. And this corresponds to answer C. Thanks for watching. Hope. This helps