In the course of various qualitative analysis procedures, the following mixtures are encountered: (d) Ag⁺ and Mn²⁺. Suggest how each mixture might be separated.

Video transcript

Hey everyone today, we're being asked to identify which re agents can be used to separate. Strong team Two plus and A. D. Plus from solution. Now, although it's not explicitly stated in the question we need to assume that both of these Catalans are present in Aquarius solutions in a creative solutions. Because only then will the scalability rules that we need to use apply for the re agents that we're using. So with that in mind we can go ahead and start taking a look at our re agents. Now we need to find out which re agent or which set of agents will help us precipitate out one of the Catalans while leaving the other in solution so that we can separate them easily. Starting with the 1st 16 molar hydrochloric acid, it'll end up forming two products with both the Catalans. Will I end up having strontium chloride, 28 di chloride SRC L. Two and silver chloride. Now, as a rule of thumb, generally chlorine, bromine and iodine will end up forming soluble salts with most metals. However, there are exceptions to this rule, one of which is silver, the others are lead and mercury but silver ends up making the salt that is formed through the reaction of chlorine insoluble. So this will actually be insoluble. So right there since this is insoluble but the strontium chloride is not this will remain soluble. This actually means that our answer is the very first option choice answer choice A With six more hydrochloric acid. We can also rule out the other ones. Excuse me. Because for be the or hydrogen sulfide would end up forming two soluble salts, and the same could go for the ammonium sulfide at two molar hydrochloric acid, it would still form or soluble salts, and even the phosphates would be soluble but not nearly as soluble as the salt. Earlier. I hope this helps, and I look forward to seeing you all in the next one.