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Ch.17 - Additional Aspects of Aqueous Equilibria
Chapter 17, Problem 17b

(b) Calculate the percent ionization of 0.0075 M butanoic acid in a solution containing 0.085 M sodium butanoate.

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Identify the chemical equilibrium involved: Butanoic acid (C₃H₇COOH) partially ionizes in water to form butanoate ions (C₃H₇COO⁻) and hydrogen ions (H⁺).
Recognize that this is a buffer solution problem, as it contains a weak acid (butanoic acid) and its conjugate base (sodium butanoate).
Use the Henderson-Hasselbalch equation to find the pH of the solution: \( \text{pH} = \text{pK}_a + \log \left( \frac{[\text{A}^-]}{[\text{HA}]} \right) \), where \([\text{A}^-]\) is the concentration of the conjugate base and \([\text{HA}]\) is the concentration of the acid.
Calculate the percent ionization using the formula: \( \text{Percent Ionization} = \left( \frac{[\text{H}^+]}{[\text{HA}]} \right) \times 100 \% \), where \([\text{H}^+]\) is the concentration of hydrogen ions at equilibrium.
Substitute the values obtained from the Henderson-Hasselbalch equation and the initial concentration of butanoic acid into the percent ionization formula to find the percent ionization.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Ionization of Weak Acids

Weak acids, like butanoic acid, do not completely dissociate in solution. Instead, they establish an equilibrium between the undissociated acid and its ions. The degree to which a weak acid ionizes can be quantified, and this is crucial for calculating percent ionization, which indicates how much of the acid has converted to ions.
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Henderson-Hasselbalch Equation

The Henderson-Hasselbalch equation relates the pH of a buffer solution to the concentration of the acid and its conjugate base. In this case, butanoic acid and sodium butanoate form a buffer system. This equation is essential for determining the pH, which is necessary for calculating the percent ionization of the weak acid in the presence of its salt.
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Percent Ionization Calculation

Percent ionization is calculated by taking the concentration of ionized acid at equilibrium, dividing it by the initial concentration of the acid, and multiplying by 100. This metric provides insight into the strength of the acid and its behavior in solution, especially when influenced by the presence of a conjugate base, as seen with sodium butanoate.
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Related Practice
Open Question
Use information from Appendix D to calculate the pH of (a) a solution that is 0.060 M in potassium propionate (C2H5COOK or KC3H5O2) and 0.085 M in propionic acid (C2H5COOH or HC3H5O2). (b) a solution that is 0.075 M in trimethylamine (CH3)3N and 0.10 M in trimethylammonium chloride (CH3)3NHCl. (c) a solution that is made by mixing 50.0 mL of 0.15 M acetic acid and 50.0 mL of 0.20 M sodium acetate.
Open Question
Use information from Appendix D to calculate the pH of: (a) a solution that is 0.250 M in sodium formate (HCOONa) and 0.100 M in formic acid (HCOOH); (b) a solution that is 0.510 M in pyridine (C5H5N) and 0.450 M in pyridinium chloride (C5H5NHCl); (c) a solution that is made by combining 55 mL of 0.050 M hydrofluoric acid with 125 mL of 0.10 M sodium fluoride.
Textbook Question

(a) Calculate the percent ionization of 0.0075 M butanoic acid 1Ka = 1.5 * 10-52.

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Textbook Question

(a) Calculate the percent ionization of 0.125 M lactic acid 1Ka = 1.4 * 10-42.

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Open Question
Which of the following solutions is a buffer? (a) 0.10 M CH3COOH and 0.10 M CH3COONa, (b) 0.10 M CH3COOH, (c) 0.10 M HCl and 0.10 M NaCl, (d) both a and c, (e) all of a, b, and c.
Textbook Question

Which of the following solutions is a buffer? (a) A solution made by mixing 100 mL of 0.100 M CH3COOH and 50 mL of 0.100 M NaOH, (b) a solution made by mixing 100 mL of 0.100 M CH3COOH and 500 mL of 0.100 M NaOH, (c) A solution made by mixing 100 mL of 0.100 M CH3COOH and 50 mL of 0.100 M HCl, (d) A solution made by mixing 100 mL of 0.100 M CH3COOK and 50 mL of 0.100 M KCl.

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