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Ch.16 - Acid-Base Equilibria

Chapter 16, Problem 94

The fluoride ion reacts with water to produce HF. (c) Is fluoride acting as a Lewis acid or as a Lewis base when reacting with water?

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Hello, everyone. Today, we have the following problem. Ammonia reacts with boron, try fluoride to form the ad acct, which is the following species there identify the Lewis acid in this reaction. So first, let's draw this reaction, we have ammonia NH three plus hour boron fluoride. And this is going to form this adult here, which is just the combination of two species. And so let's make a note of what a Lewis asset is. So a Lewis acid can generally be one of three things. It can be a hydrogen that is bonded to an electro negative atom such as flooring oxygen or nitrogen. A Lewis acid can also be a positively charged ion is a positively charged ion. And a Lewis acid can also be a central atom can be a central atom With fewer than eight valence electrons. And so let's examine our reaction here. So we have our ammonia NH three if we look at our nitrogen nitrogen has a full valence based on its bonding pattern. And so this is not a Lewis acid or L A if we look at our boron, try fluoride, boron is actually a special element and it does not have a full octet or a full valence. Soberon doesn't have a full valence. And based on our criteria, we said this was going to be representative of a Lewis acid. So in short, our boron try fluoride is our Lewis acid overall. I hope this helped. And until next time.
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