Skip to main content
Ch.14 - Chemical Kinetics
Chapter 14, Problem 74b

You have studied the gas-phase oxidation of HBr by O2: 4 HBr(g) + O2(g) → 2 H2O(g) + 2 Br2(g)
You find the reaction to be first order with respect to HBr and first order with respect to O2. You propose the following mechanism:
HBr(g) + O2(g) → HOOBr(g)
HOOBr(g) + HBr(g) → 2 HOBr(g)
HOBr(g) + HBr(g) → H2O(g) + Br2(g)
(b) Based on the experimentally determined rate law, which step is rate determining?

Verified Solution

Video duration:
4m
This video solution was recommended by our tutors as helpful for the problem above.
Was this helpful?

Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Rate Law

The rate law of a reaction expresses the relationship between the rate of a chemical reaction and the concentration of its reactants. It is determined experimentally and indicates how the rate depends on the concentration of each reactant, often represented as rate = k[A]^m[B]^n, where k is the rate constant, and m and n are the orders of the reaction with respect to reactants A and B, respectively.
Recommended video:
Guided course
01:52
Rate Law Fundamentals

Rate Determining Step (RDS)

The rate determining step is the slowest step in a reaction mechanism that dictates the overall rate of the reaction. It is crucial because even if other steps are faster, the RDS limits how quickly the entire reaction can proceed. Identifying the RDS helps in understanding the kinetics of the reaction and is often inferred from the rate law.
Recommended video:
Guided course
01:15
Rate Law Determination

Mechanism of Reaction

A reaction mechanism is a step-by-step description of the pathway taken by reactants to form products. Each step in the mechanism represents a single molecular event, and the overall reaction is the sum of these steps. Understanding the mechanism is essential for predicting the rate law and identifying the rate determining step, as it provides insight into how reactants interact and transform during the reaction.
Recommended video:
Guided course
03:06
Reaction Mechanism Overview
Related Practice
Textbook Question

The decomposition of hydrogen peroxide is catalyzed by iodide ion. The catalyzed reaction is thought to proceed by a two-step mechanism:

H2O2(aq) + I-(aq) → H2O(l) + IO-(aq) (slow)

IO-(aq) + H2O2(aq) → H2O(l) + O2(g) + I-(aq) (fast)

(c) Assuming that the first step of the mechanism is rate determining, predict the rate law for the overall process.

1668
views
Textbook Question

The reaction 2 NO1g2 + Cl21g2¡2 NOCl1g2 was performed and the following data were obtained under conditions of constant 3Cl24:

(a) Is the following mechanism consistent with the data? NO1g2 + Cl21g2ΔNOCl21g2 1fast2 NOCl21g2 + NO1g2¡2 NOCl1g2 1slow2

292
views
Textbook Question

You have studied the gas-phase oxidation of HBr by O2: 4 HBr(g) + O2(g) → 2 H2O(g) + 2 Br2(g)

You find the reaction to be first order with respect to HBr and first order with respect to O2. You propose the following mechanism:

HBr(g) + O2(g) → HOOBr(g)

HOOBr(g) + HBr(g) → 2 HOBr(g)

HOBr(g) + HBr(g) → H2O(g) + Br2(g)

(a) Confirm that the elementary reactions add to give the overall reaction.

346
views
Textbook Question

(c) Do catalysts affect the overall enthalpy change for a reaction, the activation energy, or both?

574
views
Textbook Question

(a) Most commercial heterogeneous catalysts are extremely finely divided solid materials. Why is particle size important?

522
views
Textbook Question

The addition of NO accelerates the decomposition of N2O, possibly by the following mechanism: NO1g2 + N2O1g2¡N21g2 + NO21g2 2 NO21g2¡2 NO1g2 + O21g2 (b) Is NO serving as a catalyst or an intermediate in this reaction?

955
views