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Ch.14 - Chemical Kinetics
Chapter 14, Problem 62

Understanding the high-temperature behavior of nitrogen oxides is essential for controlling pollution generated in automobile engines. The decomposition of nitric oxide (NO) to N2 and O2 is second order with a rate constant of 0.0796 M-1s-1 at 737 _x001E_C and 0.0815 M-1s-1 at 947 _x001E_C. Calculate the activation energy for the reaction.

Verified step by step guidance
1
Step 1: Use the Arrhenius equation, which relates the rate constant (k) to the activation energy (Ea), temperature (T), and the pre-exponential factor (A): k = A * e^(-Ea/(RT)), where R is the gas constant (8.314 J/mol·K).
Step 2: Take the natural logarithm of both sides of the Arrhenius equation to linearize it: ln(k) = ln(A) - Ea/(RT).
Step 3: Set up two equations using the given rate constants and temperatures. Convert the temperatures from Celsius to Kelvin by adding 273.15.
Step 4: Use the two equations to eliminate ln(A) and solve for Ea. This can be done by subtracting one equation from the other, resulting in: ln(k2/k1) = -Ea/R * (1/T2 - 1/T1).
Step 5: Rearrange the equation to solve for Ea: Ea = -R * ln(k2/k1) / (1/T2 - 1/T1). Substitute the known values for k1, k2, T1, and T2 to find the activation energy.