The reaction between ethyl iodide and hydroxide ion in ethanol 1C2H5OH2 solution, C2H5I1alc2 + OH- 1alc2 ¡ C2H5OH1l2 + I - 1alc2, has an activation energy of 86.8 kJ>mol and a frequency factor of 2.10 * 1011 M-1 s-1. (c) Which reagent in the reaction is limiting, assuming the reaction proceeds to completion?

Video transcript

Hi everyone here we have a question telling us that the reaction of methyl chloride with hydroxide ion in methanol solution is shown below methyl chloride plus hydroxide forms methanol plus chlorine. A 500 millimeter solution of sodium hydroxide is prepared by dissolving 0.350 g of sodium hydroxide in methanol. On the other hand, a 500 millimeter methyl chloride solution was prepared by dissolving 0.400 g of methyl chloride and methanol determine the limiting re agent when equal volumes of the two solutions are mixed, assume that the reaction goes to completion. The reaction is a 1-1 ratio. So the reaction with the fewer moles is going to be the limiting reaction. So first we're going to calculate our moles of hydroxide. So our molar mass of sodium hydroxide is .99 g per mole. Our mass of sodium plus zero g per mole. Our mass of oxygen plus 1.8 g per mole are mass of hydrogen And that equals 39.998 g per mole Are moles of hydroxide is going to equal 0. grams of sodium hydroxide times one mole of sodium hydroxide over its smaller mass. So 39. g sodium hydroxide times one mole of hydroxide divided by one mole of sodium hydroxide equals 8. times 10 to the -3 moles of hydroxide. Now we're going to do the same thing for our moles of methyl chloride. So our molar mass of methyl chloride is 12 0. grams per mole for our carbon Plus 1. g per mole times three Plus 35. grams per mole for our coin. And that equals 50. grams per mole Are moles of metal chloride is going to equal 0.400 g of meth chloride times one mole, Divided by its smaller mass, which we calculate to be 50.484. So our grams here are canceling out And that equals 7.923, 3 times 10 to the - moles. And this is less than 8.7504 times to the -3 moles. So this is going to be our limiting and that is our final answer. Thank you for watching. Bye.