The rate of disappearance of HCl was measured for the following reaction: CH3OH1aq2 + HCl1aq2¡CH3Cl1aq2 + H2O1l2 The following data were collected: Time (min) 3HCl 4 1M2 0.0 1.85 54.0 1.58 107.0 1.36 215.0 1.02 430.0 0.580 (c) Which is greater, the average rate between t = 54.0 and t = 215.0 min, or between t = 107.0 and t = 430.0 min?

Video transcript

Hello everyone today. We have the following problem. The data below shows the rate of disappearance of A B. In the following reaction. Is the average rate between t. Equals 72 minutes and 2 88 minutes greater than the average rate between minutes and 144 minutes. So recalling the reaction is given by the following formula the rate of it. So we're gonna have, the rate was equal to one Over. It's gonna be negative one over a. Times the change of the concentration of A. Over time. And that is going to equal one over B. Times the change in concentration of B. Over time. And so the rate of disappearance for A. B. Is simply going to be, the rate is equal to negative. We have the change in the concentration of A. B. Over time. So we're gonna first look at me too, We're gonna look at our And 1 44. So if we're gonna calculate the rate for this, the rate is equal to negative. On the outside. We have 1.28 and that comes from the time being 1 44. We're gonna subtract that by 1.78. Which is coming from 36. We were going to divide that by 1:44 minutes, subtracted by 36 minutes. And this is going to give us a value of 0.0046 molar per minute. If we do the same for our time equaling minutes to our 288, That should be T. is equal to 288. We're going to have the rate equaling -1.03 -1. Divided by R288 -172, giving us 0.23 molar per minute. So we can conclude that the average rate Is greater. So the average rate between our 36. So we're gonna say the average rate between our T equals 36 our T equals 1 is greater, then that of our T equals T equals 2 88. And with that we have answered the question overall. I hope this helped. And until next time.