Here we're told what is the internal energy of the system if the reaction is done at a constant pressure of 20 atmospheres and the volume compresses to 10 liters to 5 liters while releasing 92.2 kilojoules of heat. All right, so internal energy is ΔE and it equals Q + W. They tell us that we're releasing 92.2 kilojoules of heat. Remember, if you're releasing heat, it has a negative sign, so it's -92.2 kilojoules.
Since heat is in kilojoules, work needs to be in kilojoules. Remember, work equals negative. Pressure times change in volume, so -20.0 atmospheres times change in volume, which is final minus initial, so 5 liters, -10 liters. So here when we do that, that's going to give me a positive 100 liters times atmospheres, and here we need kilojoules for work, so we're going to have to do some converting.
So we have 100 liters times atmospheres. Remember one liter times at one liter times atmospheres equals one O 1.325 Joules. And then remember one KJ is equal to 10 to the three joules. So that's going to give me one 0.13 25 joules. Here we'll just round to 10.13 Joules. I'll killjoules. Now we're going to take that and plug it in O. Here I'm going to take this is my work and plug it into here.
So now we're going to plug this into our calculators, and when we do, that's going to give us the internal energy of our system. So let me rewrite it down here. So we're going to say ΔE = Q + W, so it equals -92.2 plus 10.13. So when we do that, we're going to get our answer as -82.07 kilojoules. This tells me how much energy my system has lost through this process. So just remember internal energy equals Q + W.