Consider the gas-phase reaction: H2(g) + I2(g) → 2 HI(g) The reaction was experimentally determined to be first order in H2 and first order in I2. Consider the proposed mechanisms. Proposed mechanism I: H2(g) + I2(g) → 2 HI(g) Single step Proposed mechanism II: I2(g) Δk1k-12 I(g) Fast H2( g) + 2 I( g) → k22 HI( g) Slow b. What kind of experimental evidence might lead you to favor mechanism II over mechanism I?
Ch.14 - Chemical Kinetics
Chapter 14, Problem 108
What rate law corresponds to the proposed mechanism for the formation of hydrogen iodide, which can be written in simplified form as: I2 Δk1k-1 2I (Fast), I + H2 Δk2k-2 H2I (Fast), H2I + I ¡k3 2HI (Slow)?

1
Identify the slow step in the mechanism, as it determines the rate law. In this case, the slow step is: \( \text{H}_2\text{I} + \text{I} \xrightarrow{k_3} 2\text{HI} \).
Write the rate law based on the slow step. The rate of the reaction is determined by the concentration of the reactants in the slow step: \( \text{Rate} = k_3 [\text{H}_2\text{I}][\text{I}] \).
Express the intermediate \( \text{H}_2\text{I} \) in terms of the initial reactants using the fast equilibrium steps. From the second fast step: \( \text{I} + \text{H}_2 \rightleftharpoons \text{H}_2\text{I} \), we have \( K_2 = \frac{[\text{H}_2\text{I}]}{[\text{I}][\text{H}_2]} \).
Solve for \( [\text{H}_2\text{I}] \) in terms of \( [\text{I}] \) and \( [\text{H}_2] \) using the equilibrium constant \( K_2 \): \( [\text{H}_2\text{I}] = K_2 [\text{I}][\text{H}_2] \).
Substitute \( [\text{H}_2\text{I}] \) from the previous step into the rate law: \( \text{Rate} = k_3 K_2 [\text{I}]^2 [\text{H}_2] \). This is the rate law for the overall reaction.
Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Rate Law
A rate law expresses the relationship between the rate of a chemical reaction and the concentration of its reactants. It is typically formulated as rate = k[A]^m[B]^n, where k is the rate constant, and m and n are the orders of the reaction with respect to reactants A and B. Understanding how to derive the rate law from a proposed reaction mechanism is crucial for predicting how changes in concentration affect the reaction rate.
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Rate Law Fundamentals
Reaction Mechanism
A reaction mechanism is a step-by-step description of the pathway taken during a chemical reaction, detailing each elementary step involved. Each step can have different rates, and the slowest step, known as the rate-determining step, dictates the overall reaction rate. Analyzing the proposed mechanism helps in identifying which steps contribute to the rate law and how intermediates are involved.
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Reaction Mechanism Overview
Elementary Steps and Rate-Determining Step
Elementary steps are individual reactions that occur in a mechanism, each with its own rate constant. The rate-determining step is the slowest step in the mechanism, which limits the overall rate of the reaction. In the given mechanism, identifying the slow step allows us to derive the rate law by focusing on the concentrations of the reactants involved in that step, while considering the fast steps as equilibria.
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Rate Law Determination
Related Practice
Textbook Question
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Textbook Question
Consider the reaction: 2 NH3(aq) + OCl-(aq) → N2H4(aq) + H2O(l) + Cl- (aq) This three-step mechanism is proposed: NH3(aq) + OCl- (aq) Δk1k2 NH2Cl(aq) + OH- (aq) Fast NH2Cl(aq) + NH3(aq) →k3 N2H5+ (aq) + Cl- (aq) Slow N2H5+ (aq) + OH-(aq) →k4 N2H4(aq) + H2O(l) Fast a. Show that the mechanism sums to the overall reaction.
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Open Question
What rate law corresponds to the proposed mechanism for the formation of hydrogen bromide, which can be written in a simplified form as: Br2(g) → 2Br(g) (Fast) Br(g) + H2(g) → HBr(g) + H(g) (Slow) H(g) + Br2(g) → HBr(g) + Br(g) (Fast)?
Textbook Question
A certain substance X decomposes. Fifty percent of X remains after 100 minutes. How much X remains after 200 minutes if the reaction order with respect to X is (c) second order?
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Textbook Question
The half-life for radioactive decay (a first-order process) of plutonium- 239 is 24,000 years. How many years does it take for one mole of this radioactive material to decay until just one atom remains?
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Open Question
The energy of activation for the decomposition of 2 mol of HI to H2 and I2 in the gas phase is 185 kJ. The heat of formation of HI(g) from H2(g) and I2(g) is -5.65 kJ/mol. Find the energy of activation for the reaction of 1 mol of H2 and 1 mol of I2 to form 2 mol of HI in the gas phase.