If the following solutions are mixed, is the resulting solution acidic, basic, or neutral? (a) 65.0 mL of 0.0500 M HClO4 and 40.0 mL of 0.0750 M NaOH

Video transcript

Hello everyone today you have the falling problem determine whether the final solution obtained is acidic, basic or neutral. When 75 mL of 750.345 molar hydrochloric acid and 60 mL of 600.3 90 Mueller of potassium hydroxide are mixed. So the first thing I wanna make note is a our hydrochloric acid is a strong acid and our potassium hydroxide is a strong base. And so because and because we have these, This is going to result in our products being a salt plus water or H20. So our reaction is going to be our hydrochloric acid plus our potassium hydroxide. This is going to form our assault which is potassium chloride and liquid water. And so we need to determine the number of moles of reactant to determine which one is in excess. And so if a hydrochloric acid is an access it'll be acidic. And if potassium hydroxide is in excess it will be basic. If the moles are equal then the final solution will be neutral. Of course. So with that we need to find the number of moles that we have. So we have our volume of our hydrochloric acid. But we need to first find We have our 75 ml. We're gonna convert that to leaders by using the conversion factor that one leader is equal to 10 to the third milliliters. And when our units cancel out, we're left with 0.75 liters. Then to find the moles of that the most of our hydrochloric acid. That's going to be our polarity times our volume. And so our polarity was our . moles over leader and most of the leaders. The units from polarity multiply bar volume which was 0.75 liters units canceled. We're left with 0.26 moles of hydrochloric acid. Now we need to do the same thing with our potassium as before. We're gonna find the volume of our potassium. We're gonna take our 60 ml, convert that to leaders by using a conversion factor that one leader is equal to 10 to the third middle leaders. When our units cancel, we're left with .06 leaders. We're going to find the number of moles of potassium hydroxide by multiplying the malaria T by our volume and we had a .390 moles per liter. Multiplied by the volume that we just sold for which was .060 L. And our units will cancel out And we will be given .0234 moles of potassium hydroxide As we see here. And based on the chemical reaction they react in a 1-1-1 mole ratio, meaning that we have a coefficient of one in front of our hydrochloric acid and potassium hydroxide. So we need .0234 more point of hydrochloric acid to neutralize point 0234 moles of potassium hydroxide. So these are essentially supposed to be equal therefore when we calculate this or the difference, We're going to have our 0.026 Most of hydrochloric acid -0.0234 moles of potassium hydroxide. We're going to get 0.002875 moles of excess, meaning that our final solution is going to be acidic. And so with that we have answered the question overall, I hope this helped, and until next time.