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Ch.7 - Periodic Properties of the Elements
Chapter 7, Problem 99a

Hydrogen is an unusual element because it behaves in some ways like the alkali metal elements and in other ways like nonmetals. Its properties can be explained in part by its electron configuration and by the values for its ionization energy and electron affinity. (a) Explain why the electron affinity of hydrogen is much closer to the values for the alkali elements than for the halogens.

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1. Electron affinity is the energy change that occurs when an electron is added to a neutral atom to form a negative ion. It is a measure of the attraction of the atom for the added electron.
2. Hydrogen has an electron configuration of 1s1. This means it has one electron in its outermost shell, similar to alkali metals. Alkali metals also have one electron in their outermost shell, which they tend to lose in order to achieve a stable electron configuration.
3. Halogens, on the other hand, have seven electrons in their outermost shell and tend to gain one electron to achieve a stable electron configuration. This makes them have a high electron affinity.
4. Therefore, hydrogen's electron affinity is closer to the alkali metals because like them, it tends to lose its outermost electron rather than gain an electron like the halogens.
5. Additionally, the ionization energy of hydrogen is also similar to that of alkali metals. Ionization energy is the energy required to remove an electron from a neutral atom. Hydrogen, like alkali metals, has a relatively low ionization energy because it is easier to remove one electron from the outermost shell.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Electron Affinity

Electron affinity is the energy change that occurs when an electron is added to a neutral atom in the gas phase. For hydrogen, its electron affinity is relatively high, indicating a strong tendency to gain an electron, which is more similar to alkali metals that also have a strong desire to achieve a stable electron configuration. This contrasts with halogens, which have higher electron affinities due to their already high electronegativity and tendency to gain electrons.
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Ionization Energy

Ionization energy is the energy required to remove an electron from a neutral atom. Hydrogen has a relatively low ionization energy compared to halogens, which means it can easily lose its single electron. This property aligns more closely with alkali metals, which also have low ionization energies, making hydrogen's behavior more akin to these metals in certain chemical contexts.
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Electron Configuration

The electron configuration of an atom describes the distribution of electrons among the various orbitals. Hydrogen has a simple electron configuration of 1s¹, which allows it to exhibit properties of both alkali metals and nonmetals. This configuration leads to its unique ability to form bonds and interact with other elements, influencing its electron affinity and overall chemical behavior.
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Related Practice
Textbook Question

Identify two ions that have the following ground-state electron configurations: (c) [Kr]5s24d10

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Textbook Question

Which of the following chemical equations is connected to the definitions of (a) the first ionization energy of oxygen (i) O1g2 + e-¡O-1g2 (ii) O1g2¡O+1g2 + e- (iii) O1g2 + 2 e-¡O2-1g2 (iv) O1g2¡O2+1g2 + 2 e- (v) O+1g2¡O2+1g2 + e-

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Textbook Question
The electron affinities, in kJ>mol, for the group 11 and group 12 metals are as follows: Cu -119 Zn 7 0 Ag -126 Cd 7 0 Au -223 Hg 7 0 (b) Why do the electron affinities of the group 11 elements become more negative as we move down the group? [Hint: Examine the trends in the electron affinities of other groups as we proceed down the periodic table.]

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Textbook Question

The first ionization energy of the oxygen molecule is the energy required for the following process: O21g2¡O2 +1g2 + e- The energy needed for this process is 1175 kJ>mol, very similar to the first ionization energy of Xe. Would you expect O2 to react with F2? If so, suggest a product or products of this reaction.

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Textbook Question

It is possible to define metallic character as we do in this book and base it on the reactivity of the element and the ease with which it loses electrons. Alternatively, one could measure how well electricity is conducted by each of the elements to determine how 'metallic' the elements are. On the basis of conductivity, there is not much of a trend in the periodic table: Silver is the most conductive metal, and manganese the least. Look up the first ionization energies of silver and manganese; which of these two elements would you call more metallic based on the way we define it in this book?

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Textbook Question

Which of the following is the expected product of the reaction of K(s) and H2(g)? (i) KH(s), (ii) K2H(s), (iii) KH2(s), (iv) K2H2(s), or (v) K(s) and H2(g) will not react with one another.

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