Identify the Lewis acid and Lewis base from among the reactants in each equation. b. AlBr₃ + NH₃ ⇌ H₃NAlBr₃ c. F^–(aq) + BF₃(aq) ⇌ BF₄^–(aq)

Video transcript

Hello. For the following reaction, we are asked to determine the Lewis acid and Lewis base from the reactant. Let's begin by recalling that a Lewis acid is an electron pair except er and that a Lewis base is an electron pair donor. One of our reactant is ammonia, which has a lone pair of electrons. And so it has a pair of electrons it can donate. So this will be our Lewis base. Our other reactant is gallium fluoride. Gallium is in period four. So it's filling the four S 23 D and then the four p orbital's, it only has one electron in the four p orbital's which means then that it can accept electrons. So gallium fluoride will be our Lewis acid. So, ammonia with its lone pair and act as electron pair donor. So this is our Lewis base and gallium fluoride with empty orbital's can accept electrons. So this is our Lewis acid. Thanks for watching. Hope this helped.