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Ch. 5 - Systems and Matrices
Lial - College Algebra 13th Edition
Lial13th EditionCollege AlgebraISBN: 9780136881063Not the one you use?Change textbook
Chapter 6, Problem 109

Solve each problem. See Examples 5 and 9. Solve the system of equations (4), (5), and (6) from Example 9.
25x+40y+20z=220025x + 40y + 20z = 2200 (4)
4x+2y+3z=2804x + 2y + 3z = 280 (5)
3x+2y+z=1803x + 2y + z = 180 (6)

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1
Start by writing down the system of equations clearly: \[25x + 40y + 20z = 2200\] \[4x + 2y + 3z = 280\] \[3x + 2y + z = 180\]
Choose two of the equations to eliminate one variable. For example, subtract equation (6) multiplied by an appropriate number from equation (5) multiplied by another number to eliminate variable \( y \). This will give you an equation with only \( x \) and \( z \).
Next, use the result from step 2 and one of the original equations (for example, equation (6)) to eliminate another variable, such as \( z \), to solve for \( x \) alone.
Once you have the value of \( x \), substitute it back into one of the two-variable equations from step 2 to find \( z \).
Finally, substitute the values of \( x \) and \( z \) into any of the original equations to solve for \( y \).

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Systems of Linear Equations

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