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Ch. 10 - Photosynthesis

Chapter 10, Problem 8

Which of the following correctly identify a role of the ATP produced in the light-capturing reactions? Select True or False for each statement. T/F It is used by rubisco to fix CO2 to RuBP. T/F It serves the same role as ATP produced by mitochondria. T/F It is used to regenerate RuBP from G3P molecules. T/F It is used to produce G3P molecules

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Hello everyone. Let's look at our next problem. It says both A. T. P. And N A. D N A. D. P. H. Two produced during the light reactions are and let's look over our choices real quick. We've got a sources of energy for the Calvin cycle. Be used in the Calvin cycle to convert carbon dioxide into sugar. C. Both A and B and D. None of these. So here's an example of why it's good to look over your answer choices first because we see we have one choice that involves both A and B. Being correct and one choice that involves none of the answers being correct. So, always good to know that that is a possibility. So let's think about our light reactions and A. T. P and N. A. D. P. H. Two that are produced. Well, both of those are high energy molecules um A T. P of course being the ultimate high energy molecule. Even more so than N A D. P. H two. And in those light reactions of photosynthesis, they essentially harness energy from sunlight and then the energy stored in A. T. P and N A. D. P. H. Two is used in the Calvin cycle in those steps that need the input of energy. So choice A sources of energy for the Calvin cycle is correct. I'm not going to pick that as my answer because I know that one option is that both A and B. Are correct. Little dots show that it is correct. So then let's think about choice be used in the Calvin cycle to convert carbon dioxide into sugar. When we think about the fixation of carbon dioxide in the Calvin cycle. Remember from our content video that carbon dioxide combines with the five carbon molecule R U B p. It produces a brief six carbon intermediate which ends up breaking into 23 carbon molecules called three P. G. A. Or phosphate glycerin. It well, we then use A. T. P. So I'll start with three P G. A. Here we consume A T. P. Oops. Yeah, about that. A T. P. And it don't gives a phosphate to this three P G A. To become 13 B p G A. Or 13 This phosphor glass rate. So we've used up a molecule of A T. P. And then this 1 3. This fossil glass right, is reduced by N A D ph two to become G three P or glycerol to hide three phosphate. This is a three carbon molecule and we'll end up after another turn of the Calvin cycle, Becoming the six carbon sugar, glucose. So we see in that pathway from carbon dioxide to be converted into glucose. We actually are using up some 80 P and some N A D. P H two in the steps of that cycle, converting carbon dioxide into sugar. So B is also correct. So A and B. Are both correct. So C. Is our correct answer. Obviously D none of these cannot be our answer. So that gets crossed out and then A and B are crossed out, since we have the option of C, both A and B. So again, both 80 P and N A D p H two produced during light reactions are see both A and B. There are sources of energy for the Calvin cycle, and they're also used in the Calvin cycle, converting carbon dioxide into sugar. See you in the next video.