Chapter 36, Problem 6
A plant cell with a ΨS of −0.65 MPa maintains a constant volume when bathed in a solution that has a ΨS of −0.30 MPa and is in an open container. The cell has a a. ΨP of +0.65 MPa. b. Ψ of −0.65 MPa. c. ΨP of +0.35 MPa. d. ΨP of 0 MPa.
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Movement of phloem sap from a source to a sink a. occurs through the apoplast of sieve-tube elements. b. depends ultimately on the activity of proton pumps. c. depends on tension, or negative pressure potential. d. results mainly from diffusion.
Photosynthesis ceases when leaves wilt, mainly because a. the chlorophyll in wilting leaves is degraded. b. accumulation of CO2 in the leaf inhibits enzymes. c. stomata close, preventing CO2 from entering the leaf. d. photolysis, the water-splitting step of photosynthesis, cannot occur when there is a water deficiency.
What would enhance water uptake by a plant cell? a. decreasing the Ψ of the surrounding solution b. positive pressure on the surrounding solution c. the loss of solutes from the cell d. increasing the Ψ of the cytoplasm
Compared with a cell with few aquaporin proteins in its membrane, a cell containing many aquaporin proteins will a. have a faster rate of osmosis. b. have a lower water potential. c. have a higher water potential. d. accumulate water by active transport.
Which of the following would tend to increase transpiration? a. spiny leaves b. sunken stomata c. a thicker cuticle d. higher stomatal density