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Ch. 36 - Resource Acquisition and Transport in Vascular Plants

Chapter 36, Problem 6

A plant cell with a ΨS of −0.65 MPa maintains a constant volume when bathed in a solution that has a ΨS of −0.30 MPa and is in an open container. The cell has a a. ΨP of +0.65 MPa. b. Ψ of −0.65 MPa. c. ΨP of +0.35 MPa. d. ΨP of 0 MPa.

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Hello everyone here We have a question asking us if a plant cell has a solid potential of negative 0.5 mega pascal's and a pressure potential of 0.2 mega pascal's, what will be the water potential? So we find water potential by adding our solid potential plus our pressure potential. So our water potential Is going to equal negative 0.5 mega pascal's plus 0.2 mega pascal's. So that is going to equal negative 0. mega pascal's. So our answer is a negative 0. mega pascal's. Thank you for watching. Bye.