Skip to main content
Pearson+ LogoPearson+ Logo
Ch. 14 - Mendel and the Gene Idea
All textbooksCampbell 12th EditionCh. 14 - Mendel and the Gene IdeaProblem 8
Previous problem
Next problem

Chapter 14, Problem 8

What is the probability that each of the following pairs of parents will produce the indicated offspring? (Assume independent assortment of all gene pairs.) a. AABBCC×aabbcc→AaBbCc b. AABbCc×AaBbCc→AAbbCC c. AaBbCc×AaBbCc→AaBbCc d. aaBbCC×AABbcc→AaBbCc

Verified Solution
Video duration:
2m
This video solution was recommended by our tutors as helpful for the problem above.
Was this helpful?

Video transcript

Hello everyone here we have a question asking us to assume that independent assortment happens in all gene pairs. And the question is what will be the probability of capital A capital A capital B. Lower case speed? Capital C. Lower case C. And capital A lowercase A. Capital B. Capital B. Capital C capital C. Parental genotype producing offspring with capital A lowercase A capital B. Lowercase B. Capital C. Lower case C. Genotype. So we're going to make a public square for each of these. So we have capital A. Capital A capital A lowercase A. Gives us capital a capital A capital A capital A capital A lowercase A capital A lowercase A. And then with B. We have capital B. Lower case B. Capital B. Capital B. So we have capital B. Capital B. Capital B. Lowercase B. Capital B. Capital B. Capital B. Lowercase B. And lastly we have capital C. Lower K. C. Capital C. Capital C. So we'll get capital C. Capital C. Capital C. Lower case C. Capital C. Capital C capital C. Lower case C. So we want capital A lowercase A. Which is one half of our first opponent square. We want capital B. Lowercase B. Which is one half of our second punnett square. We want capital C. Lower case C. Which is one half of our third square. So now we need to multiply all three probabilities. So one half times one half times one half equals 1/8. So that is our answer. So our answer is c. Thank you for watching. Bye
Previous problem
Next problem
Related Practice
Textbook Question

Flower position, stem length, and seed shape are three characters that Mendel studied. Each is controlled by an independently assorting gene and has dominant and recessive expression as indicated in Table 14.1. If a plant that is heterozygous for all three characters is allowed to self-fertilize, what proportion of the offspring would you expect to be each of the following? (Note: Use the rules of probability instead of a huge Punnett square.) a. homozygous for the three dominant traits b. homozygous for the three recessive traits c. heterozygous for all three characters d. homozygous for axial and tall, heterozygous for seed shape

1419
views
Textbook Question

Hemochromatosis is an inherited disease caused by a recessive allele. If a woman and her husband, who are both carriers, have three children, what is the probability of each of the following? a. All three children are of normal phenotype. b. One or more of the three children have the disease. c. All three children have the disease. d. At least one child is phenotypically normal.

1380
views
Textbook Question

The genotype of F1 individuals in a tetrahybrid cross is AaBbCcDd. Assuming independent assortment of these four genes, what are the probabilities that F2 offspring will have the following genotypes? a. aabbccdd b. AaBbCcDd c. AABBCCDD d. AaBBccDd e. AaBBCCdd

3295
views
Textbook Question

Karen and Steve each have a sibling with sickle-cell disease. Neither Karen nor Steve nor any of their parents have the disease, and none of them have been tested to see if they carry the sickle-cell allele. Based on this incomplete information, calculate the probability that if this couple has a child, the child will have sickle-cell disease.

1810
views
Textbook Question

In 1981, a stray black cat with unusual rounded, curled-back ears was adopted by a family in California. Hundreds of descendants of the cat have since been born, and cat fanciers hope to develop the curl cat into a show breed. Suppose you owned the first curl cat and wanted to develop a true-breeding variety. How would you determine whether the curl allele is dominant or recessive? How would you obtain true-breeding curl cats? How could you be sure they are true-breeding?

728
views
Textbook Question

In tigers, a recessive allele of a particular gene causes both an absence of fur pigmentation (a white tiger) and a cross-eyed condition. If two phenotypically normal tigers that are heterozygous at this locus are mated, what percentage of their offspring will be cross-eyed? What percentage of cross-eyed tigers will be white?

1479
views