Skip to main content
Ch. 14 - Mendel and the Gene Idea
Chapter 14, Problem 7

The genotype of F1 individuals in a tetrahybrid cross is AaBbCcDd. Assuming independent assortment of these four genes, what are the probabilities that F2 offspring will have the following genotypes? a. aabbccdd b. AaBbCcDd c. AABBCCDD d. AaBBccDd e. AaBBCCdd

Verified step by step guidance
1
Step 1: Understand that each gene pair (Aa, Bb, Cc, Dd) segregates independently during gamete formation. This means each allele has a 1/2 chance of being passed on to the F2 generation.
Step 2: Calculate the probability for each genotype by multiplying the probabilities of obtaining each specific allele. For example, the probability of getting 'aa' from 'Aa x Aa' is (1/2 * 1/2) = 1/4.
Step 3: Apply the multiplication rule to find the probability of the genotype 'aabbccdd'. Since each gene pair is homozygous recessive, the probability is (1/4)^4 = 1/256.
Step 4: For the genotype 'AaBbCcDd', each gene pair must be heterozygous. The probability for each gene pair to be heterozygous is 1/2 * 1/2 = 1/4. Thus, the probability for 'AaBbCcDd' is (1/4)^4 = 1/256.
Step 5: Similarly, calculate the probabilities for 'AABBCCDD' (1/256), 'AaBBccDd' (1/256), and 'AaBBCCdd' (1/256), by considering the required combination of alleles for each gene.

Verified Solution

Video duration:
1m
This video solution was recommended by our tutors as helpful for the problem above.
Was this helpful?

Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Independent Assortment

Independent assortment is a fundamental principle of genetics stating that alleles for different genes segregate independently of one another during gamete formation. This means that the inheritance of one trait will not affect the inheritance of another, allowing for a variety of combinations in offspring genotypes.
Recommended video:
Guided course
08:49
Independent Assortment

Punnett Square

A Punnett square is a diagram used to predict the genotype and phenotype combinations of offspring from a genetic cross. By organizing the possible gametes from each parent, it allows for a visual representation of the probabilities of different genotypes in the offspring, making it easier to calculate expected ratios.
Recommended video:
Guided course
01:37
Punnett Squares

Genotype Probability Calculation

Calculating genotype probabilities involves determining the likelihood of specific allele combinations in offspring based on parental genotypes. For a tetrahybrid cross like AaBbCcDd, the probability of each genotype can be calculated by multiplying the probabilities of each individual gene's alleles, considering their independent assortment.
Recommended video:
03:30
A. Calculating Genotype Frequency from Allele Frequency
Related Practice
Textbook Question

DRAW IT Two pea plants heterozygous for the characters of pod color and pod shape are crossed. Draw a Punnett square to determine the phenotypic ratios of the offspring.


2038
views
Textbook Question

Flower position, stem length, and seed shape are three characters that Mendel studied. Each is controlled by an independently assorting gene and has dominant and recessive expression as indicated in Table 14.1. If a plant that is heterozygous for all three characters is allowed to self-fertilize, what proportion of the offspring would you expect to be each of the following? (Note: Use the rules of probability instead of a huge Punnett square.) a. homozygous for the three dominant traits b. homozygous for the three recessive traits c. heterozygous for all three characters d. homozygous for axial and tall, heterozygous for seed shape

1534
views
Textbook Question

Hemochromatosis is an inherited disease caused by a recessive allele. If a woman and her husband, who are both carriers, have three children, what is the probability of each of the following? a. All three children are of normal phenotype. b. One or more of the three children have the disease. c. All three children have the disease. d. At least one child is phenotypically normal.

1508
views
Textbook Question

What is the probability that each of the following pairs of parents will produce the indicated offspring? (Assume independent assortment of all gene pairs.) a. AABBCC×aabbcc→AaBbCc b. AABbCc×AaBbCc→AAbbCC c. AaBbCc×AaBbCc→AaBbCc d. aaBbCC×AABbcc→AaBbCc

2314
views
Textbook Question

Karen and Steve each have a sibling with sickle-cell disease. Neither Karen nor Steve nor any of their parents have the disease, and none of them have been tested to see if they carry the sickle-cell allele. Based on this incomplete information, calculate the probability that if this couple has a child, the child will have sickle-cell disease.

1935
views
Textbook Question

In 1981, a stray black cat with unusual rounded, curled-back ears was adopted by a family in California. Hundreds of descendants of the cat have since been born, and cat fanciers hope to develop the curl cat into a show breed. Suppose you owned the first curl cat and wanted to develop a true-breeding variety. How would you determine whether the curl allele is dominant or recessive? How would you obtain true-breeding curl cats? How could you be sure they are true-breeding?

815
views