Which one of the following equations has solution 0?

a. arctan 1 = x

b. arccos 0 = x

c. arcsin 0 = x

Video transcript

Identify the equation which has a solution equal to pi divided by three. But we have four possible answers. X equals cosine in verse one, X equals 10, inverse square root of three, X equals sine in verse one half or X equals cosine in verse squared of three divided by two. Now, with this problem, let's first rewrite all of our answers. So we have X equals Kan in verse one which al rewrites by taking cosine of both sides, we would have cosine X equals one. If we rewrote this, we'll do the same for all of our answers tangent X equals square to three sine, X equals one F cosine X equals square root of three divided by two. Now let's see if any of these match up with our angle pi divided by three. If we look at our unit circle, I divided by three is in quadrant one, we can see at pi divided by three, we have X equals one half, Y equals squared of three divided by two. Now we know that X corresponds to the cosine of the unit circle, meaning we have cosine equals one half and the same for S with Y now I look at our possible answers, we don't see a single one that matches with any of these. However, we can test out the tangent, you know, the tangent is sine divided by cosine. And we can write this as a square of three, divided by two, all divided by one half. When simplified that equals the square root of three, we now get 10 X equals a square of three, which means the answer to our problem. His answer B 10 and verse of the square of three. OK. I hope to help you solve the problem. Thanks for watching. Goodbye.