In Exercises 5–8, let v = -5i + 2j and w = 2i - 4j Find the specified vector, scalar, or angle. v ⋅ w

Video transcript

Hello, today we're going to be calculating the following scalar using the given vectors. So we are told that vector A is equal to six I plus J. And we are also told that vector B is I minus 27 J. We want to use these two vectors to calculate the dot product of A dot B. So in order to calculate A dot product, what we'll need to do is we'll need to multiply the I components of the A and B vector together and multiply the J components of the A and B vector together. Then we're going to want to take the sum of the two products. So using that method, the dot product of A dot B will be defined as six multiplied by one plus one multiplied by negative 27 six, multiplied by one will give us the value of six and one multiplied by negative 27 will give us the value of negative 27 and finally six minus 27 will give us a final value of negative 21. So that means the dot product of A dot B is going to be negative 21. And with that being said, the answer to this problem is going to be b so I hope this video helps you in understanding how to approach this problem. And I'll go ahead and see you all in the next video.