In Exercises 1–4, u and v have the same direction. In each exercise: Find ||u||.

Video transcript

Or the given vectors A and B B, the magnitude of A and B in us. Here we have a graph with two vectors vector A between two points and vector B between two points. And we have four possible answers all with different measures of magnitude for vectors A and B. Now to solve this, we need to find the magnitude of both vectors. Since we have two points, we can make use of the distance formula between two points on the left. This will allow us to find our magnitude of the vector. The distance formula is given by D equals the square root of X two minus X one squared plus Y two minus Y one squared. You will have T equals square root are both our points. Let's say we want to want to find magnitude a first for magnitude A. We will take our second X value 25 subtract negative two and then square it, we will do the same for our Y components 19 minus 19 square. This gives us the square root of 27 squared plus zero squared, which gives us a square of 27 squared which is just itself. Now let's find the magnitude of vector B. We will do the same thing where we have the square root of 30 minus three squared costs negative two minus negative two square. We look at 27 squared plus zero squared, which gives the square root of 27 squared, which just gives us back out 27. We now have the magnitude of vector A and the magnitude of vector B. If we look at our possible answers, we determine answer B is the answer to our problem. OK. I hope to help you solve the problem. Thank you for watching. Goodbye.