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Ch. 4 - Laws of Sines and Cosines; Vectors
Blitzer - Trigonometry 3rd Edition
Blitzer3rd EditionTrigonometryISBN: 9780137316601Not the one you use?Change textbook
Chapter 4, Problem 37

In Exercises 21–38, let u = 2i - 5j, v = -3i + 7j, and w = -i - 6j. Find each specified vector or scalar.
||w - u||

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1
Identify the vectors given: \( \mathbf{u} = 2\mathbf{i} - 5\mathbf{j} \), \( \mathbf{w} = -\mathbf{i} - 6\mathbf{j} \).
Calculate the vector difference \( \mathbf{w} - \mathbf{u} \) by subtracting the components of \( \mathbf{u} \) from \( \mathbf{w} \):
\[ \mathbf{w} - \mathbf{u} = (-1 - 2)\mathbf{i} + (-6 - (-5))\mathbf{j} \]
Simplify the components to get the resulting vector:
\[ \mathbf{w} - \mathbf{u} = (-3)\mathbf{i} + (-1)\mathbf{j} \]
Find the magnitude (or norm) of the vector \( \mathbf{w} - \mathbf{u} \) using the formula for the length of a vector in 2D:
\[ ||\mathbf{w} - \mathbf{u}|| = \sqrt{(-3)^2 + (-1)^2} \]

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Vector Subtraction

Vector subtraction involves finding the difference between two vectors by subtracting their corresponding components. For vectors u and w, w - u is computed by subtracting each component of u from the corresponding component of w, resulting in a new vector.
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Magnitude (Norm) of a Vector

The magnitude of a vector is its length in the coordinate plane, calculated using the Pythagorean theorem. For a vector with components (x, y), the magnitude is √(x² + y²). This gives a scalar representing the vector's size.
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Component Form of Vectors

Vectors in two dimensions can be expressed in component form as ai + bj, where a and b are the components along the x- and y-axes respectively. Understanding this form allows for straightforward operations like addition, subtraction, and magnitude calculation.
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