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Ch. 2 - Acute Angles and Right Triangles
Lial - Trigonometry 12th Edition
Lial12th EditionTrigonometryISBN: 9780136552161Not the one you use?Change textbook
Chapter 3, Problem 2.5.33

Solve each problem. See Examples 3 and 4. Height of an Antenna A scanner antenna is on top of the center of a house. The angle of elevation from a point 28.0 m from the center of the house to the top of the antenna is 27°10', and the angle of elevation to the bottom of the antenna is 18°10'. Find the height of the antenna.

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1
Identify the points involved: the point on the ground 28.0 m from the house center, the bottom of the antenna (top of the house), and the top of the antenna. The horizontal distance from the observation point to the house center is 28.0 m.
Convert the given angles from degrees and minutes to decimal degrees or use them as is in trigonometric functions. For example, 27°10' means 27 degrees and 10 minutes, where 1 minute = 1/60 degrees.
Use the tangent function, which relates the angle of elevation to the opposite side (height) and adjacent side (horizontal distance). For the bottom of the antenna (top of the house), set up the equation: \(\tan(18^{\circ}10') = \frac{h_{house}}{28.0}\), where \(h_{house}\) is the height of the house.
Similarly, for the top of the antenna, set up the equation: \(\tan(27^{\circ}10') = \frac{h_{house} + h_{antenna}}{28.0}\), where \(h_{antenna}\) is the height of the antenna.
Solve the first equation for \(h_{house}\), then substitute into the second equation to solve for \(h_{house} + h_{antenna}\). Finally, subtract \(h_{house}\) from this result to find the height of the antenna: \(h_{antenna} = (h_{house} + h_{antenna}) - h_{house}\).

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Angle of Elevation

The angle of elevation is the angle formed between the horizontal line from the observer's eye and the line of sight to an object above the horizontal. It helps determine the height of objects by relating distances and angles in right triangles.
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Right Triangle Trigonometry

Right triangle trigonometry uses sine, cosine, and tangent ratios to relate the angles and sides of right triangles. In this problem, tangent is used to connect the height of the antenna and the horizontal distance from the observer.
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45-45-90 Triangles

Difference of Heights Using Angles

By calculating the heights corresponding to two different angles of elevation (top and bottom of the antenna) from the same horizontal distance, the height of the antenna is found by subtracting the lower height from the higher one.
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Related Practice
Textbook Question

Find a value of θ in the interval [0°, 90°) that satisfies each statement. Give answers in decimal degrees to six decimal places. See Example 2.

cos θ = 0.85536428

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Textbook Question

(Modeling) Fish's View of the World The figure shows a fish's view of the world above the surface of the water. (Data from Walker, J., 'The Amateur Scientist,' Scientific American.) Suppose that a light ray comes from the horizon, enters the water, and strikes the fish's eye. Assume that this ray gives a value of 90° for angle θ₁ in the formula for Snell's law. (In a practical situation, this angle would probably be a little less than 90°.) The speed of light in water is about 2.254 x 10⁸ m per sec. Find angle θ₂ to the nearest tenth.

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Textbook Question

CONCEPT PREVIEW Match each trigonometric function value or angle in Column I with its appropriate approximation in Column II.


Column I: 1.

cot⁻¹ 30

Column II:

A. 88.09084757°

B. 63.25631605°

C. 1.909152433°

D. 17.45760312°

E. 0.2867453858

F. 1.962610506

G. 14.47751219°

H. 1.015426612

I. 1.051462224

J. 0.9925461516

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Textbook Question

Find two angles in the interval [0°, 360°) that satisfy each of the following. Round answers to the nearest degree. tan θ = 1.3763819

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Textbook Question

Determine whether each statement is true or false. If false, tell why. Use a calculator for Exercises 39 and 42. 1 tan² 60° = sec² 60°

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Textbook Question

Use a calculator to approximate the value of each expression. Give answers to six decimal places. tan 11.7689°

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