Solve the given quadratic equation using the square root property.
$2x^2-16=0$

$x=0,x=-2$

$x=4$\sqrt$2,x=-4$\sqrt$2$

$x=4,x=-4$

$x=2$\sqrt$2,x=-2$\sqrt$2$

Verified step by step guidance

Start by isolating the term with the variable squared. The given equation is 2x^2 - 16 = 0. Add 16 to both sides to get 2x^2 = 16.

Next, divide both sides of the equation by 2 to solve for x^2. This gives x^2 = 8.

Now, apply the square root property. The square root property states that if x^2 = a, then x = ±√a. Apply this to x^2 = 8 to get x = ±√8.

Simplify the square root of 8. Note that √8 can be simplified to 2√2, because 8 = 4 * 2 and √4 = 2.

Thus, the solutions to the equation are x = 2√2 and x = -2√2.

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Solve the given quadratic equation using the square root property. 2x2−16=02x^2-16=02x2−16=0