Table of contents
- 0. Review of College Algebra4h 43m
- 1. Measuring Angles39m
- 2. Trigonometric Functions on Right Triangles2h 5m
- 3. Unit Circle1h 19m
- 4. Graphing Trigonometric Functions1h 19m
- 5. Inverse Trigonometric Functions and Basic Trigonometric Equations1h 41m
- 6. Trigonometric Identities and More Equations2h 34m
- 7. Non-Right Triangles1h 38m
- 8. Vectors2h 25m
- 9. Polar Equations2h 5m
- 10. Parametric Equations1h 6m
- 11. Graphing Complex Numbers1h 7m
1. Measuring Angles
Angles in Standard Position
3:36 minutes
Problem 70b
Textbook Question
Textbook Question(Modeling) Grade Resistance Solve each problem. See Example 3. Find the grade resistance, to the nearest ten pounds, for a 2400-lb car traveling on a -2.4° downhill grade.
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Grade Resistance
Grade resistance refers to the force opposing the motion of a vehicle due to the incline or decline of the road. It is calculated based on the weight of the vehicle and the angle of the grade. A negative grade indicates a downhill slope, which reduces the effective weight of the vehicle acting against gravity.
Trigonometric Functions
Trigonometric functions, such as sine and cosine, relate the angles of a triangle to the ratios of its sides. In the context of grade resistance, these functions help determine the vertical and horizontal components of the weight of the vehicle based on the angle of the grade. Understanding these functions is essential for calculating forces acting on the vehicle.
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Force Calculation
Force calculation involves determining the net force acting on an object, which is essential for understanding motion. In this scenario, the force due to gravity acting on the car must be resolved into components to find the grade resistance. This requires applying Newton's laws of motion and understanding how forces interact on inclined planes.
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