Graph each function over a two-period interval. y = sin [2(x + π/4) ] + 1/2
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Identify the standard form of the sine function: \( y = a \sin(b(x - c)) + d \). Here, \( a = 1 \), \( b = 2 \), \( c = -\frac{\pi}{4} \), and \( d = \frac{1}{2} \).
Determine the amplitude of the function, which is the absolute value of \( a \). In this case, the amplitude is \( |1| = 1 \).
Calculate the period of the function using the formula \( \frac{2\pi}{b} \). For this function, the period is \( \frac{2\pi}{2} = \pi \).
Identify the phase shift, which is given by \( -c \). Here, the phase shift is \( -(-\frac{\pi}{4}) = \frac{\pi}{4} \) to the right.
Determine the vertical shift, which is \( d = \frac{1}{2} \). This means the entire graph is shifted up by \( \frac{1}{2} \) units.
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Sine Function
The sine function is a periodic function that describes the relationship between the angle of a right triangle and the ratio of the length of the opposite side to the hypotenuse. It oscillates between -1 and 1, with a period of 2π. Understanding the sine function is crucial for graphing, as it provides the foundational shape of the graph that will be modified by transformations.
Transformations involve shifting, stretching, or compressing the graph of a function. In the given function, y = sin[2(x + π/4)] + 1/2, the '2' indicates a vertical compression (or horizontal stretch), while '(x + π/4)' represents a horizontal shift to the left by π/4. The '+ 1/2' shifts the entire graph upward by 1/2 unit, affecting the midline of the sine wave.
Graphing a function over a specified interval, such as a two-period interval, requires understanding the periodic nature of the sine function. For y = sin[2(x + π/4)] + 1/2, the period is π (since the coefficient of x is 2), meaning the function will complete one full cycle every π units. Therefore, to graph over a two-period interval, one would plot the function from x = -π/4 to x = 7π/4.