Solve the given quadratic equation using the quadratic formula.
Table of contents
- 0. Review of College Algebra4h 45m
- 1. Measuring Angles40m
- 2. Trigonometric Functions on Right Triangles2h 5m
- 3. Unit Circle1h 19m
- 4. Graphing Trigonometric Functions1h 19m
- 5. Inverse Trigonometric Functions and Basic Trigonometric Equations1h 41m
- 6. Trigonometric Identities and More Equations2h 34m
- 7. Non-Right Triangles1h 38m
- 8. Vectors2h 25m
- 9. Polar Equations2h 5m
- 10. Parametric Equations1h 6m
- 11. Graphing Complex Numbers1h 7m
0. Review of College Algebra
Solving Quadratic Equations
Problem R.42
Textbook Question
Solve each quadratic equation using the zero-factor property. See Example 5.
x² + 2x - 8 = 0
Verified step by step guidance1
Start with the quadratic equation given: \(x^{2} + 2x - 8 = 0\).
Factor the quadratic expression on the left side. Look for two numbers that multiply to \(-8\) and add to \$2$.
Write the factored form as \((x + a)(x + b) = 0\), where \(a\) and \(b\) are the numbers found in the previous step.
Apply the zero-factor property, which states that if \((x + a)(x + b) = 0\), then either \(x + a = 0\) or \(x + b = 0\).
Solve each linear equation separately to find the values of \(x\).
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Zero-Factor Property
The zero-factor property states that if the product of two factors is zero, then at least one of the factors must be zero. This principle is used to solve quadratic equations by factoring the equation into two binomials and setting each equal to zero to find the solutions.
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Factoring
Factoring Quadratic Equations
Factoring involves rewriting a quadratic equation in the form ax² + bx + c = 0 as a product of two binomials. This process requires finding two numbers that multiply to ac and add to b, enabling the equation to be expressed as (x + m)(x + n) = 0.
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Factoring
Solving Quadratic Equations
Once factored, solving quadratic equations involves applying the zero-factor property by setting each factor equal to zero and solving for x. This yields the roots or solutions of the equation, which can be real or complex numbers depending on the discriminant.
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