In Exercises 53–56, let u = -2i + 3j, v = 6i - j, w = -3i. Find each specified vector or scalar. ||u + v||² - ||u - v||²
Table of contents
- 0. Review of College Algebra4h 45m
- 1. Measuring Angles40m
- 2. Trigonometric Functions on Right Triangles2h 5m
- 3. Unit Circle1h 19m
- 4. Graphing Trigonometric Functions1h 19m
- 5. Inverse Trigonometric Functions and Basic Trigonometric Equations1h 41m
- 6. Trigonometric Identities and More Equations2h 34m
- 7. Non-Right Triangles1h 38m
- 8. Vectors2h 25m
- 9. Polar Equations2h 5m
- 10. Parametric Equations1h 6m
- 11. Graphing Complex Numbers1h 7m
8. Vectors
Geometric Vectors
Problem 43
Textbook Question
In Exercises 39–46, find the unit vector that has the same direction as the vector v.
v = 3i - 2j
Verified step by step guidance1
Identify the given vector \( \mathbf{v} = 3\mathbf{i} - 2\mathbf{j} \). This means the vector components are \( (3, -2) \).
Calculate the magnitude (length) of the vector \( \mathbf{v} \) using the formula:
\[ \\|\mathbf{v}\\| = \\sqrt{(3)^2 + (-2)^2} = \\sqrt{9 + 4} \]
Simplify the expression under the square root to find the magnitude:
\[ \\|\mathbf{v}\\| = \\sqrt{13} \]
To find the unit vector in the same direction as \( \mathbf{v} \), divide each component of \( \mathbf{v} \) by its magnitude:
\[ \mathbf{u} = \left( \frac{3}{\\|\mathbf{v}\\|}, \frac{-2}{\\|\mathbf{v}\\|} \right) \]
Write the unit vector explicitly as:
\[ \mathbf{u} = \left( \frac{3}{\\sqrt{13}}, -\frac{2}{\\sqrt{13}} \right) \] which is the vector with length 1 pointing in the same direction as \( \mathbf{v} \).
Verified video answer for a similar problem:This video solution was recommended by our tutors as helpful for the problem above
Video duration:
4mPlay a video:
0 Comments
Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Vector Components and Notation
A vector in two dimensions can be expressed using unit vectors i and j, representing the x and y directions respectively. For example, v = 3i - 2j means the vector has an x-component of 3 and a y-component of -2. Understanding this notation is essential for manipulating and analyzing vectors.
Recommended video:
i & j Notation
Magnitude of a Vector
The magnitude (or length) of a vector v = ai + bj is found using the Pythagorean theorem: |v| = √(a² + b²). This scalar value represents the distance from the origin to the point defined by the vector components and is crucial for normalizing vectors.
Recommended video:
Finding Magnitude of a Vector
Unit Vector and Normalization
A unit vector has a magnitude of 1 and points in the same direction as the original vector. To find it, divide each component of the vector by its magnitude. This process, called normalization, produces a vector that preserves direction but standardizes length.
Recommended video:
Unit Vector in the Direction of a Given Vector
Related Videos
Related Practice
Textbook Question
799
views
