- 0. Review of College Algebra4h 43m
- 1. Measuring Angles39m
- 2. Trigonometric Functions on Right Triangles2h 5m
- 3. Unit Circle1h 19m
- 4. Graphing Trigonometric Functions1h 19m
- 5. Inverse Trigonometric Functions and Basic Trigonometric Equations1h 41m
- 6. Trigonometric Identities and More Equations2h 34m
- 7. Non-Right Triangles1h 38m
- 8. Vectors2h 25m
- 9. Polar Equations2h 5m
- 10. Parametric Equations1h 6m
- 11. Graphing Complex Numbers1h 7m
5. Inverse Trigonometric Functions and Basic Trigonometric Equations
Evaluate Composite Trig Functions
Problem 45
Textbook Question
In Exercises 39–54, find the exact value of each expression, if possible. Do not use a calculator. tan (tan⁻¹ 125)

1
Recognize that \( \tan^{-1} \) is the inverse function of \( \tan \), meaning \( \tan(\tan^{-1}(x)) = x \) for all \( x \) in the domain of \( \tan^{-1} \).
Identify the domain of \( \tan^{-1}(x) \), which is all real numbers, \( (-\infty, \infty) \).
Since 125 is a real number, it falls within the domain of \( \tan^{-1}(x) \).
Apply the property of inverse functions: \( \tan(\tan^{-1}(125)) = 125 \).
Conclude that the exact value of the expression \( \tan(\tan^{-1}(125)) \) is simply 125.
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Inverse Trigonometric Functions
Inverse trigonometric functions, such as tan⁻¹ (arctangent), are used to find the angle whose tangent is a given number. For example, tan⁻¹(125) gives the angle θ such that tan(θ) = 125. Understanding this concept is crucial for evaluating expressions involving inverse functions.
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Tangent Function
The tangent function, denoted as tan(θ), is a fundamental trigonometric function defined as the ratio of the opposite side to the adjacent side in a right triangle. It is also expressed as tan(θ) = sin(θ)/cos(θ). Recognizing how the tangent function operates is essential for simplifying expressions involving angles.
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Composition of Functions
Composition of functions involves applying one function to the result of another. In this case, we are evaluating tan(tan⁻¹(125)), which simplifies to 125 because the tangent function and its inverse cancel each other out. Understanding function composition is key to solving problems that involve nested functions.
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