Determine the amplitude, period, and phase shift of each function. Then graph one period of the function. y = sin (x − π/2)
Verified step by step guidance
1
Identify the general form of the sine function: \(y = A \sin(B(x - C))\), where \(A\) is the amplitude, \(\frac{2\pi}{B}\) is the period, and \(C\) is the phase shift.
Compare the given function \(y = \sin(x - \frac{\pi}{2})\) to the general form. Here, \(A = 1\) (coefficient of sine), \(B = 1\) (coefficient of \(x\) inside the sine), and \(C = \frac{\pi}{2}\).
Calculate the amplitude as the absolute value of \(A\): \(\text{Amplitude} = |1| = 1\).
Calculate the period using the formula \(\text{Period} = \frac{2\pi}{B} = \frac{2\pi}{1} = 2\pi\).
Determine the phase shift, which is \(C = \frac{\pi}{2}\), meaning the graph shifts to the right by \(\frac{\pi}{2}\). Then, to graph one period, plot the sine curve starting at \(x = \frac{\pi}{2}\) and ending at \(x = \frac{\pi}{2} + 2\pi\).
Verified video answer for a similar problem:
This video solution was recommended by our tutors as helpful for the problem above
Video duration:
7m
Play a video:
0 Comments
Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Amplitude of a Sine Function
Amplitude is the maximum value or height of the sine wave from its midline. For y = sin(x − π/2), the amplitude is 1, as the coefficient of the sine function is 1. It determines how far the graph stretches vertically.
The period is the length of one complete cycle of the sine wave. For y = sin(bx), the period is calculated as 2π divided by |b|. Since b = 1 here, the period is 2π, meaning the function repeats every 2π units along the x-axis.
Phase shift refers to the horizontal translation of the sine graph. It is found by solving (x − c) inside the function, where c is the phase shift. For y = sin(x − π/2), the graph shifts π/2 units to the right.