We just saw how to use our even-odd identities in order to rewrite expressions with negative arguments, and we specifically saw our arguments with negative angle measures in them. But you're actually more often going to have to simplify expressions that just have variables rather than angle measures. So let's take a look at that here. Here we're asked to use our even-odd identities in order to rewrite the expression with no negative arguments in terms of just one trigonometric function. So here, in our first example, we have the negative tangent of negative theta. Now, this is already in terms of just one trigonometric function, but we need to get rid of that negative argument there. I know that the tangent of negative theta is equal to negative tangent of theta. So, I can simply replace the tangent of negative theta using that identity. I want to make sure that I'm paying attention to everything that I need to keep here, so make sure that you're still keeping that negative on the outside. Then the tangent of negative theta, I can replace that with negative tangent of theta. Now I see here that I have two negative signs and I know that two negatives make a positive, so this ends up just being a positive tangent of theta. And now, we have successfully rewritten this with no negative arguments in terms of just one trigonometric function. So we're done with that example there. Let's move on to our second example. Here we're asked to rewrite this expression, the sine of negative theta over the cosine of negative theta. Now here I can go ahead and use my even-odd identities for sine and cosine. And I know that the sine of negative theta is equal to negative sine of theta. Then the cosine of negative theta, because it's an even function, is simply equal to the cosine of theta. Now from here, we have gotten rid of those negative arguments, but it's still in terms of two trig functions. So how can we simplify this further? Well, the sine over the cosine is simply the tangent. So keeping that negative sign, this ends up just being negative tangent of theta - sin ( θ ) cos ( θ ) and that's my final answer here. Now you might have seen a different way to do this and that's totally fine. There are always multiple ways to simplify. Then using our even-odd identity for tangent, we know that the tangent of negative theta is simply equal to negative tangent of theta, so we would end up getting that exact same answer, negative tangent of theta. Now it doesn't matter which way you choose to simplify this because you'll get the right answer regardless. Now that we've seen how to do this using variables, let's continue practicing. Thanks for watching, and I'll see you in the next one.
Table of contents
- 0. Fundamental Concepts of Algebra3h 29m
- 1. Equations and Inequalities3h 27m
- 2. Graphs1h 43m
- 3. Functions & Graphs2h 17m
- 4. Polynomial Functions1h 54m
- 5. Rational Functions1h 23m
- 6. Exponential and Logarithmic Functions2h 28m
- 7. Measuring Angles39m
- 8. Trigonometric Functions on Right Triangles2h 5m
- 9. Unit Circle1h 19m
- 10. Graphing Trigonometric Functions1h 19m
- 11. Inverse Trigonometric Functions and Basic Trig Equations1h 41m
- 12. Trigonometric Identities 2h 34m
- 13. Non-Right Triangles1h 38m
- 14. Vectors2h 25m
- 15. Polar Equations2h 5m
- 16. Parametric Equations1h 6m
- 17. Graphing Complex Numbers1h 7m
- 18. Systems of Equations and Matrices1h 6m
- 19. Conic Sections2h 36m
- 20. Sequences, Series & Induction1h 15m
- 21. Combinatorics and Probability1h 45m
- 22. Limits & Continuity1h 49m
- 23. Intro to Derivatives & Area Under the Curve2h 9m
12. Trigonometric Identities
Introduction to Trigonometric Identities
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