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Ch 36: Diffraction
Chapter 35, Problem 36

Diffraction occurs for all types of waves, including sound waves. High-frequency sound from a distant source with wavelength 9.00 cm passes through a slit 12.0 cm wide. A microphone is placed 8.00 m directly in front of the center of the slit, corresponding to point O in Fig. 36.5a . The microphone is then moved in a direction perpendicular to the line from the center of the slit to point O. At what distances from O will the intensity detected by the microphone be zero?

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1
Identify the given values: wavelength (λ) of the sound wave is 9.00 cm, width of the slit (a) is 12.0 cm, and the distance from the slit to the microphone (L) is 8.00 m.
Convert all measurements to the same unit, preferably meters, for consistency in calculations.
Use the formula for the minima in diffraction patterns, which occurs at angles (θ) satisfying the equation \(a \sin(\theta) = m\lambda\), where \(m\) is the order of the minimum (m = ±1, ±2, ±3, ...).
Calculate the angle (θ) for each order (m) using the equation from step 3. Remember that \(\sin(\theta) = \frac{m\lambda}{a}\).
Determine the positions along the perpendicular direction from point O where the intensity is zero by using the relationship \(x = L \tan(\theta)\), where \(x\) is the distance from point O at which the intensity is zero.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Diffraction

Diffraction is the bending of waves around obstacles and the spreading of waves when they pass through narrow openings. This phenomenon occurs for all types of waves, including sound, light, and water waves. The extent of diffraction depends on the wavelength of the wave relative to the size of the opening or obstacle. In this scenario, the sound waves will diffract as they pass through the slit, affecting the intensity detected by the microphone.
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Interference

Interference is the phenomenon that occurs when two or more waves overlap and combine to form a new wave pattern. This can result in constructive interference, where wave amplitudes add together, or destructive interference, where they cancel each other out. In the context of the microphone's position, points of zero intensity correspond to locations where destructive interference occurs due to the path difference between waves arriving from different parts of the slit.
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Path Difference

Path difference refers to the difference in distance traveled by two waves arriving at a point from different sources. For destructive interference to occur, the path difference must equal an odd multiple of half the wavelength. In this problem, as the microphone is moved, the varying path differences from the sound waves passing through the slit will determine the points where the intensity is zero, based on the wavelength of the sound and the geometry of the setup.
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Related Practice
Textbook Question
If the planes of a crystal are 3.50 Å (1 Å = 10-10 m = 1 Ångstrom unit) apart, (a) what wavelength of electromagnetic waves is needed so that the first strong interference maximum in the Bragg reflection occurs when the waves strike the planes at an angle of 22.0°, and in what part of the electromagnetic spectrum do these waves lie?
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Textbook Question
Parallel rays of green mercury light with a wavelength of 546 nm pass through a slit covering a lens with a focal length of 60.0 cm. In the focal plane of the lens, the distance from the central maximum to the first minimum is 8.65 mm. What is the width of the slit?
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Textbook Question
Light of wavelength 585 nm falls on a slit 0.0666 mm wide. (a) On a very large and distant screen, how many totally dark fringes (indicating complete cancellation) will there be, including both sides of the central bright spot? Solve this problem without calculating all the angles! (Hint: What is the largest that sin u can be? What does this tell you is the largest that m can be?) (b) At what angle will the dark fringe that is most distant from the central bright fringe occur?
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Textbook Question
A series of parallel linear water wave fronts are traveling directly toward the shore at 15.0 cm/s on an otherwise placid lake. A long concrete barrier that runs parallel to the shore at a distance of 3.20 m away has a hole in it. You count the wave crests and observe that 75.0 of them pass by each minute, and you also observe that no waves reach the shore at +-61.3 cm from the point directly opposite the hole, but waves do reach the shore everywhere within this distance. (a) How wide is the hole in the barrier?
293
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Textbook Question
A series of parallel linear water wave fronts are traveling directly toward the shore at 15.0 cm/s on an otherwise placid lake. A long concrete barrier that runs parallel to the shore at a distance of 3.20 m away has a hole in it. You count the wave crests and observe that 75.0 of them pass by each minute, and you also observe that no waves reach the shore at +-61.3 cm from the point directly opposite the hole, but waves do reach the shore everywhere within this distance. (b) At what other angles do you find no waves hitting the shore?
310
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Textbook Question
Monochromatic light of wavelength 580 nm passes through a single slit and the diffraction pattern is observed on a screen. Both the source and screen are far enough from the slit for Fraunhofer diffraction to apply. (a) If the first diffraction minima are at +-90.0°, so the central maximum completely fills the screen, what is the width of the slit? (b) For the width of the slit as calculated in part (a), what is the ratio of the intensity at u = 45.0° to the intensity at u = 0?
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