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Ch 31: Alternating Current

Chapter 31, Problem 31

(b) What is the inductance of an inductor whose reactance is 120 Ω at 80.0 Hz?

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Welcome back, everybody. We are making observations about a coil of wire and we are told that it has a inductive reactant of 145 omegas. And we are told that it has a frequency of 1.25 kHz. And we are tasked with finding what the induct immense is of the coil. Well, we have this formula, we have that the inductive reactant is equal to an angular frequency times induct ints. But this is really the same thing as saying, two pi times frequency times the conductance. Here's what I'm gonna do. I'm gonna divide both sides by two pi times the frequency, two pi times the frequency. And you'll see that all these terms cancel out and we are left with the fact that inducted is equal to the inductive reactant divided by two pi times R frequency. We have all of our terms. So let's go ahead and plug in our values here. We have that the induct ince's equal to 1 45 divided by two pi times 1.25 times 10 to the third. And this gives us 0. Hertz or 1.85 times 10 to the negative second hurts corresponding to our final answer choice of c Thank you all so much for watching. Hope this video helped. We will see you all in the next one.
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