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Ch 23: Electric Potential

Chapter 23, Problem 23

At a certain distance from a point charge, the poten-tial and electric-field magnitude due to that charge are 4.98 V and 16.2 V/m, respectively. (Take V = 0 at infinity.) (c) Is the electric field directed toward or away from the point charge?

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Welcome back everybody. We are making observations about a charged particle that is located at the origin of the xy plane. Here we are told that at some point P away from the origin that it has a magnitude an electric field magnitude of 27.4 volts per meter. And an electric potential. I will label these as point P. Relative an electric potential of 14.1 volts. And we are tasked with finding what is the direction of the electric field at point P. Well, if you'll notice here, our potential at point P is positive and what makes a positive potential is a positive charge, meaning that our charge at the X. Y. Origin is positive. Now electric field lines go away from positive charges. So if we trace that all the way out and through point P, we will see that at point P we are moving away from the origin corresponding to our answer choice of a thank you all so much for watching. Hope this video helped. We will see you all in the next one.
Related Practice
Textbook Question
At a certain distance from a point charge, the poten-tial and electric-field magnitude due to that charge are 4.98 V and 16.2 V/m, respectively. (Take V = 0 at infinity.) (a) What is the distance to the point charge?
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An electron is to be accelerated from 3.00x10^6 m/s to 8.00x10^6 m/s. (a) Through what potential difference must the electron pass to accomplish this?
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Textbook Question
At a certain distance from a point charge, the poten-tial and electric-field magnitude due to that charge are 4.98 V and 16.2 V/m, respectively. (Take V = 0 at infinity.) (b) What is the magnitude of the charge?
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Textbook Question
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