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Ch 23: Electric Potential
Chapter 23, Problem 23

An infinitely long line of charge has linear charge den­sity 5.00x10^-12 C/m. A proton (mass 1.67x10^-27 kg, charge +1.60x10^-19 C) is 18.0 cm from the line and moving directly toward the line at 3.50x10^3 m/s. (b) How close does the proton get to the line of cha rge?

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Calculate the electric field (E) generated by the infinitely long line of charge using the formula: E = \( \frac{\lambda}{2\pi \epsilon_0 r} \), where \( \lambda \) is the linear charge density, \( \epsilon_0 \) is the permittivity of free space (approximately \( 8.85 \times 10^{-12} \) C²/(N·m²)), and r is the distance from the line of charge.
Determine the force (F) acting on the proton due to the electric field using Coulomb's Law: F = qE, where q is the charge of the proton.
Set up the equation of motion for the proton under the influence of this electric force. The net force acting on the proton provides the centripetal force required to change the direction of the proton as it moves towards the line of charge. Use the formula: F = ma, where m is the mass of the proton and a is the acceleration.
As the proton approaches the line of charge, its kinetic energy decreases due to the work done against the electric force. Set up the conservation of energy equation: Initial Kinetic Energy = Work done by the electric force + Final Kinetic Energy. Solve this equation to find the minimum distance (r_min) from the line of charge where the velocity of the proton becomes zero.
Substitute all known values into the equations and solve for r_min, the closest distance the proton gets to the line of charge.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Electric Field of a Line Charge

The electric field generated by an infinitely long line of charge can be calculated using the formula E = (λ / (2πε₀r)), where λ is the linear charge density, ε₀ is the permittivity of free space, and r is the distance from the line. This electric field points radially outward from the line if the charge is positive, affecting the motion of charged particles nearby.
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Kinematics of Charged Particles

The motion of charged particles, such as protons, in an electric field can be analyzed using kinematic equations. The force acting on the proton due to the electric field will cause it to accelerate, and its trajectory can be predicted by applying Newton's second law (F = ma) to determine how its velocity and position change over time.
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Conservation of Energy

In this scenario, the conservation of energy principle states that the total mechanical energy (kinetic plus potential) of the proton remains constant if only conservative forces are acting. As the proton moves closer to the line of charge, its kinetic energy will convert into electric potential energy, allowing us to calculate the closest approach by equating these energy forms.
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Related Practice
Textbook Question
A very large plastic sheet carries a uniform charge density of -6.00 nC/m^2 on one face. (a) As you move away from the sheet along a line perpendicular to it, does the potential increase or decrease? How do you know, without doing any calculations? Does your answer depend on where you choose the reference point for potential?
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Textbook Question
A point charge q_1=+2.40 μC is held stationary at the origin. A second point charge q_2=-4.30 μC moves from the point x=0.150 m, y=0 to the point x=0.250 m, y=0.250 m. How much work is done by the electric force on q_2?
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Textbook Question
A particle with charge +4.20 nC is in a uniform electric field E directed to the left. The charge is released from rest and moves to the left; after it has moved 6.00 cm, its kinetic energy is +2.20x10^-6 J. What is (a) the work done by the electric force?
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Textbook Question
A very long insulating cylinder of charge of radius 2.50 cm carries a uniform linear density of 15.0 nC/m. If you put one probe of a voltmeter at the surface, how far from the surface must the other probe be placed so that the voltmeter reads 175 V?
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Textbook Question
Two large, parallel conducting plates carrying op­posite charges of equal magnitude are separated by 2.20 cm. (b) What is the potential difference between the two plates?
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Textbook Question
BIO. Electrical Sensitivity of Sharks. Certain sharks can detect an electric field as weak as 1.0 μV/m. To grasp how weak this field is, if you wanted to produce it between two parallel metal plates by connecting an ordinary 1.5­V AA battery across these plates, how far apart would the plates have to be?
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