Skip to main content
Ch 13: Gravitation
Chapter 13, Problem 13

Titania, the largest moon of the planet Uranus, has 1/8 the radius of the earth and 1/1700 the mass of the earth. (b) What is the average density of Titania? (This is less than the density of rock, which is one piece of evidence that Titania is made primarily of ice.)

Verified step by step guidance
1
Step 1: Recall the formula for density, which is defined as mass divided by volume. The formula is given by \( \rho = \frac{m}{V} \), where \( \rho \) is the density, \( m \) is the mass, and \( V \) is the volume.
Step 2: Use the given information to express the mass of Titania relative to Earth's mass. Since Titania's mass is 1/1700 of Earth's mass, write it as \( m_{\text{Titania}} = \frac{1}{1700} m_{\text{Earth}} \).
Step 3: Calculate the volume of Titania using the formula for the volume of a sphere, \( V = \frac{4}{3} \pi r^3 \), where \( r \) is the radius. Given that Titania's radius is 1/8 of Earth's radius, express it as \( r_{\text{Titania}} = \frac{1}{8} r_{\text{Earth}} \) and substitute this into the volume formula to get \( V_{\text{Titania}} = \frac{4}{3} \pi \left(\frac{1}{8} r_{\text{Earth}}\right)^3 \).
Step 4: Simplify the expression for Titania's volume by calculating \( \left(\frac{1}{8} r_{\text{Earth}}\right)^3 \) and substituting back into the volume formula.
Step 5: Substitute the expressions for Titania's mass and volume into the density formula to find the average density of Titania. Simplify the expression to find the ratio of Titania's density to Earth's density.

Verified Solution

Video duration:
2m
This video solution was recommended by our tutors as helpful for the problem above.
Was this helpful?

Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Density

Density is defined as mass per unit volume, typically expressed in kilograms per cubic meter (kg/m³). It is a fundamental property of materials that helps determine their composition and behavior under various conditions. In this context, calculating the density of Titania involves using its mass and volume to understand its material composition.
Recommended video:
Guided course
8:13
Intro to Density

Volume of a Sphere

The volume of a sphere can be calculated using the formula V = (4/3)πr³, where r is the radius. This formula is essential for determining the volume of Titania, given its radius is provided. Understanding how to apply this formula allows for the calculation of Titania's volume, which is necessary for finding its density.
Recommended video:
Guided course
05:21
Volume Thermal Expansion

Comparative Planetology

Comparative planetology is the study of planets and moons by comparing their physical and chemical properties. This concept is relevant in understanding Titania's density in relation to other celestial bodies, such as Earth and ice-rich bodies. It provides context for interpreting Titania's composition and the implications of its lower density compared to rocky materials.
Recommended video:
Guided course
03:14
Comparing Buoyant Forces
Related Practice
Textbook Question
The mass of Venus is 81.5% that of the earth, and its radius is 94.9% that of the earth. (a) Compute the acceleration due to gravity on the surface of Venus from these data.
1244
views
Textbook Question
The mass of Venus is 81.5% that of the earth, and its radius is 94.9% that of the earth. (b) If a rock weighs 75.0 N on earth, what would it weigh at the surface of Venus?
748
views
Textbook Question
Titania, the largest moon of the planet Uranus, has 1/8 the radius of the earth and 1/1700 the mass of the earth. (a) What is the acceleration due to gravity at the surface of Titania?
958
views
Textbook Question
Ten days after it was launched toward Mars in December 1998, the Mars Climate Orbiter spacecraft (mass 629 kg) was 2.87 * 10^6 km from the earth and traveling at 1.20 * 10^4 km/h relative to the earth. At this time, what were (a) the spacecraft's kinetic energy relative to the earth and (b) the potential energy of the earth–spacecraft system?
1539
views
Textbook Question
On October 15, 2001, a planet was discovered orbiting around the star HD 68988. Its orbital distance was measured to be 10.5 million kilometers from the center of the star, and its orbital period was estimated at 6.3 days. What is the mass of HD 68988? Express your answer in kilograms and in terms of our sun's mass.
1312
views
Textbook Question
In March 2006, two small satellites were discovered orbiting Pluto, one at a distance of 48,000 km and the other at 64,000 km. Pluto already was known to have a large satellite Charon, orbiting at 19,600 km with an orbital period of 6.39 days. Assuming that the satellites do not affect each other, find the orbital periods of the two small satellites without using the mass of Pluto
1063
views