Skip to main content
Ch 13: Gravitation

Chapter 13, Problem 13

Titania, the largest moon of the planet Uranus, has 1/8 the radius of the earth and 1/1700 the mass of the earth. (b) What is the average density of Titania? (This is less than the density of rock, which is one piece of evidence that Titania is made primarily of ice.)

Verified Solution
Video duration:
2m
This video solution was recommended by our tutors as helpful for the problem above.
1025
views
Was this helpful?

Video transcript

Welcome back everybody. We are told that the radius of Jupiter is about 11.2 times that of the radius of Earth. We are also told that the mass of Jupiter is 317 times the mass of Earth. Now we need to determine what the density of jupiter is given, that the density of earth is 5500 kg per meter cubed. And just as one more assumption here we are told that jupiter is a sphere, which makes our calculations fairly easy. So here's what we're gonna do. We're gonna start out with the formula for the density of jupiter and try to eventually sub in this value right here. So the density of jupiter is just going to be the mass of jupiter divided by the volume of jupiter. Well, we know that the mass of jupiter is times the mass of earth. I'm just going to expand the bottom here. The volume of jupiter is going to be four thirds times pi times the radius of jupiter squared. Well, we know what the radius of jupiter is equal to this bottom part is now going to be four thirds pi times 11.2 times the radius of earth cubed. Now, I'm gonna take out some of the constants and numbers to the front here, we're gonna have 317 divided by 11.2 cubed times the mass of earth over four thirds pi times the radius of earth cubed a K. A the volume of earth, which this term right here just simplifies down to the density of earth, which we are given. So let's go ahead and plug in that value here, we have found our constant or a factor right up front. We just need to plug in the density of earth, which is 5500 kg per meter cubed, giving us that the density of jupiter is kg per meter cubed. Giving us a final answer choice of B. Thank you all so much for watching. Hope this video helped. We will see you all in the next one.
Related Practice
Textbook Question
The mass of Venus is 81.5% that of the earth, and its radius is 94.9% that of the earth. (a) Compute the acceleration due to gravity on the surface of Venus from these data.
1123
views
Textbook Question
The mass of Venus is 81.5% that of the earth, and its radius is 94.9% that of the earth. (b) If a rock weighs 75.0 N on earth, what would it weigh at the surface of Venus?
687
views
Textbook Question
Titania, the largest moon of the planet Uranus, has 1/8 the radius of the earth and 1/1700 the mass of the earth. (a) What is the acceleration due to gravity at the surface of Titania?
891
views
Textbook Question
Ten days after it was launched toward Mars in December 1998, the Mars Climate Orbiter spacecraft (mass 629 kg) was 2.87 * 10^6 km from the earth and traveling at 1.20 * 10^4 km/h relative to the earth. At this time, what were (a) the spacecraft's kinetic energy relative to the earth and (b) the potential energy of the earth–spacecraft system?
1469
views
Textbook Question
On October 15, 2001, a planet was discovered orbiting around the star HD 68988. Its orbital distance was measured to be 10.5 million kilometers from the center of the star, and its orbital period was estimated at 6.3 days. What is the mass of HD 68988? Express your answer in kilograms and in terms of our sun's mass.
1230
views
Textbook Question
In March 2006, two small satellites were discovered orbiting Pluto, one at a distance of 48,000 km and the other at 64,000 km. Pluto already was known to have a large satellite Charon, orbiting at 19,600 km with an orbital period of 6.39 days. Assuming that the satellites do not affect each other, find the orbital periods of the two small satellites without using the mass of Pluto
1007
views