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Ch 10: Dynamics of Rotational Motion

Chapter 10, Problem 10.21c

A solid ball is released from rest and slides down a hillside that slopes downward at 65.0° from the horizontal. (c) In part (a), why did we use the coefficient of static friction and not the coefficient of kinetic friction?

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Hey, everyone in this problem, a book rests on a table inclined at an angle of 30 degrees with respect to the horizontal ground level. And we are asked why should we consider static rather than kinetic friction? In this case? No, we have four answer choices. We'll go through each of them in just a minute. But the key here is that the book rests. OK. If the book rests, that means that the book is stationary. OK. So let's take a look at our answer. Choices. Option A says um kinetic friction because only kinetic friction can act on stationary objects, right? And that is not true. OK. Kinetic friction acts on moving objects. And so option A we can eliminate, OK. Option B, only static friction can act on moving objects again. That's not correct. OK. We know that static friction acts on stationary objects. And we also know that our book is stationary. OK. So we don't have a moving object. So that one's kind of wrong in two ways. Option C because the book is stationary and only static friction can act on stationary objects. So that is exactly what we have in this case. We have a stationary object because we have a stationary object, we know that only static friction can act. OK. That's gonna keep that book from sliding, that force of static friction and that, that force we have to overcome in order to get the book to start moving. And so option C is the correct answer. In this case. Thanks everyone for watching. I hope this video helped see you in the next one.
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A machine part has the shape of a solid uniform sphere of mass 225 g and diameter 3.00 cm. It is spinning about a frictionless axle through its center, but at one point on its equator it is scraping against metal, resulting in a friction force of 0.0200 N at that point. (b) How long will it take to decrease its rotational speed by 22.5 rad/s?

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Textbook Question

CP A small block on a frictionless, horizontal surface has a mass of 0.0250 kg. It is attached to a massless cord passing through a hole in the surface (Fig. E10.40). The block is originally revolving at a distance of 0.300 m from the hole with an angular speed of 2.85 rad/s. The cord is then pulled from below, shortening the radius of the circle in which the block revolves to 0.150 m. Model the block as a particle. (a) Is the angular momentum of the block conserved? Why or why not?

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Textbook Question

CP A small block on a frictionless, horizontal surface has a mass of 0.0250 kg. It is attached to a massless cord passing through a hole in the surface (Fig. E10.40). The block is originally revolving at a distance of 0.300 m from the hole with an angular speed of 2.85 rad/s. The cord is then pulled from below, shortening the radius of the circle in which the block revolves to 0.150 m. Model the block as a particle. (b) What is the new angular speed?

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