Skip to main content
Ch 14: Fluids and Elasticity
Chapter 14, Problem 16

A hammer taps on the end of a 4.00-m-long metal bar at room temperature. A microphone at the other end of the bar picks up two pulses of sound, one that travels through the metal and one that travels through the air. The pulses are separated in time by 9.00 ms. What is the speed of sound in this metal?

Verified Solution

Video duration:
3m
This video solution was recommended by our tutors as helpful for the problem above.
Was this helpful?

Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Speed of Sound

The speed of sound is the distance traveled per unit time by a sound wave as it propagates through a medium. It varies depending on the medium's properties, such as density and elasticity. In solids, sound travels faster than in liquids and gases due to closer molecular spacing, which facilitates quicker energy transfer.
Recommended video:
Guided course
05:17
Standing Sound Waves

Wave Propagation

Wave propagation refers to the movement of sound waves through different media. In this scenario, sound travels through both a metal bar and air, each with distinct speeds. The time difference in the arrival of sound pulses at the microphone allows for the calculation of the speed of sound in the metal by considering the distance and the time delay.
Recommended video:
Guided course
07:32
Transverse Velocity of Waves

Time Delay

Time delay is the difference in time between two events, in this case, the arrival of sound waves through different media. The problem states that the pulses are separated by 9.00 ms, which is crucial for determining the speed of sound in the metal. By using the known distance of the bar and the time delay, one can apply the formula for speed to find the desired value.
Recommended video:
Guided course
05:59
Velocity-Time Graphs & Acceleration