What is the force of attraction between a 50 kg woman and a 70 kg man sitting 1.0 m apart?

Video transcript

Hey, everyone. So this is a pretty straightforward gravitational force problem. Let's see what they're asking us how much gravitational attraction do an 80 kg astronaut and a 140 kg alien have on each other when they are seated 2.1 m away from each other. Our multiple choice answers here are a 3.4 times 10 to the negative six newtons. B 1.2 times 10 to the negative seven newtons C 3.4 times 10 to the negative six newtons or D 1.7 times 10 to the -7 mutants. OK. So the key to this problem is going to be recalling our gravitational force equation. So that's given by F equals G M one M two all divided by R squared. So let's take these terms one x 1 G is our gravitational constant. So we can recall that that is 6.67 times 10 to the negative 11. And those units are meters cubed per kilogram second squared M is given in the problem as 80 kg M two is given as 140 kg. And R is the distance between the two objects. So that is given as 2.1 m. So from there, it really is just a simple plug and chug. So we have the force is equal to 6.67 times 10 to the negative meters cubed per kilogram. Second squared multiplied by 80 kg, multiplied by 140 kg. All divided by 2.1 m squared Plug that into our calculator. And we get 1.7 Times 10 to the - Newtons. And that aligns with answer choice D so D is the correct answer to this problem. That's all we have for this one. We'll see you in the next video.