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Ch 13: Newton's Theory of Gravity
Chapter 13, Problem 13

Suppose we could shrink the earth without changing its mass. At what fraction of its current radius would the free-fall acceleration at the surface be three times its present value?

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1
Identify the formula for gravitational acceleration at the surface of a planet, which is given by $g = \frac{GM}{r^2}$, where $G$ is the gravitational constant, $M$ is the mass of the planet, and $r$ is the radius of the planet.
Set up the equation for the new gravitational acceleration to be three times the current gravitational acceleration. This can be expressed as $3g = \frac{GM}{r_{new}^2}$.
Substitute the original expression for $g$ into the new equation to eliminate $M$. This gives $3 \left(\frac{GM}{r^2}\right) = \frac{GM}{r_{new}^2}$.
Simplify the equation to find a relationship between the original radius $r$ and the new radius $r_{new}$. This results in $3r^2 = r_{new}^2$.
Solve for $r_{new}$ in terms of $r$ to find the fraction of the current radius at which the gravitational acceleration would be three times its current value. This is done by taking the square root of both sides, resulting in $r_{new} = \frac{r}{\sqrt{3}}$.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Gravitational Acceleration

Gravitational acceleration is the acceleration experienced by an object due to the gravitational force exerted by a massive body, such as Earth. It is denoted by 'g' and has a standard value of approximately 9.81 m/s² at Earth's surface. This acceleration depends on the mass of the Earth and the distance from its center, following the formula g = G * M / r², where G is the gravitational constant, M is the mass of the Earth, and r is the radius.
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Inverse Square Law

The inverse square law states that the strength of a physical quantity (like gravitational force) decreases with the square of the distance from the source. In the context of gravity, if the radius of a planet is reduced while keeping its mass constant, the gravitational acceleration at the surface increases because the distance to the center of mass decreases, leading to a stronger gravitational pull.
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Scaling Relationships

Scaling relationships in physics refer to how physical quantities change in relation to one another when a system is altered. In this scenario, if the radius of the Earth is reduced to achieve a specific gravitational acceleration, we can use the relationship between radius and gravitational acceleration to determine the new radius. Specifically, to achieve three times the current gravitational acceleration, the radius must be scaled down by a factor that reflects the square root of the change in acceleration.
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