What are the velocities of (b) a 75 kg skydiver falling with p = -4100j kg m/s

Video transcript

Hi, everyone in this practice problem. We're being asked to determine the velocity at which a bungee jumper is hurtling toward the ground. We are being given a 90 kg bungee jumper descending with a downward momentum of negative 3600 J kilograms meter per seconds. And we're being asked to determine the velocity at which he is going toward the ground. And the options given are a negative 40 m per second. JB 30 m per seconds. J C negative 25 m per second. J and D 48 m per second. J so I am going to start us off with uh listing out all the given information. So the mass of the bungee jumper itself, M is going to be 90 kg and the momentum given B is going to be negative 3600 J kilograms meter per second. So to find the velocity of this 90 kg uh bungee jumper falling with this negative 3600 J kilograms meters per seconds. Momentum, we can use the formula for momentum which is P equals mass multiplied by V which is velocity. So P is momentum M is mass and V is velocity and what we need to find is the velocity. So we can rearrange this formula in order to get velocity equals to P divided by M or momentum divided by the mass. So we can substitute our P and M according to the information given. So the B or the momentum is negative 3600 J kilograms meter per second Divided by M. the mass which is 90 kg. And that will actually give us a velocity value V of negative 40 J meters per seconds. So negative 40 J meters per seconds is going to be the velocity at which the bungee jumper is hurtling toward the ground, which will correspond to option A in our answer choices. So answer A is going to be the answer to this particular practice problem and that'll be all for this particular practice problem. If you guys still have any sort of confusion, please make sure to check out our other lesson videos on similar topic and that will be it for this one. Thank you.