In FIGURE EX11.5, what value of Fmax gives an impulse of 6.0 N s?

Video transcript

Hi, everyone in this practice problem, we're being asked to calculate the maximum value of the force FX so that it produces an impulse of eight Newton seconds on the object, we're being given a force versus time graph shown in the figure, we will have an FX force in Newton in the Y direction or in the Y axis and time T in seconds in the X axis. The figure itself depicts that the force F max actually started at four seconds going constantly for six seconds and stops at 10, the 10 seconds going back to zero. So the options given for the maximum value of F max are a 8.72 Newton B 5.28 Newton C, 1.33 Newton and D 2.47 Newton. So the graph of the A versus D given in our figure represents a rectangle and the, the area of a rectangle or the area of this force versus time graph is going to equals to the impulse. So area will equals to impulse and that will essentially be length multiplied by the width, the length of the A rectangle is going to be six seconds. And the wit is then going to be F max, the impulse that we were interested at is going to be eight Newton seconds. So that will give us an equation of eight Newton seconds equals to six seconds multiplied by F max calculating this. Then we can get FX by dividing 8.8 Newton seconds by six seconds. And they will give us an FX value of 1.33 Newton just like. So, so the F max is then going to be 1.33 Newton in order for us to produce an impulse of eight Newton seconds on the object, which will correspond to option C. So option C in our answer choices is going to be the answer to this particular practice problem. And that'll be all for this one. If you guys still have any sort of confusion, please make sure to check out our other lesson videos on similar topic and that'll be it. Thank you.