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Ch 04: Kinematics in Two Dimensions
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All textbooksKnight Calc 5th EditionCh 04: Kinematics in Two DimensionsProblem 4

Chapter 4, Problem 4

The radius of the earth's very nearly circular orbit around the sun is 1.5 x 10^11m. Find the magnitude of the earth's (a) velocity

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Welcome back, everybody. We are making observations about a satellite that is rotating around a planet in a circular fashion. We are told that its radius of orbit is 7,242 km with an orbital period of 101 minutes. And we are tasked with finding what is the speed of the satellite. Well, we know that the speed of the satellite is just equal to two pi times the radius of orbit divided by the period. So let's go ahead and plug in our values. We have that V is equal to two pi times 7242. But we want this in meters. So I multiply it by 10 to the third, divided by 100 and one minutes. But I want this in seconds. So I multiply it by 60 multiplying straight across. This gives us 7.5 times 10 to the third meters per second corresponding to our final answer. Choice of B Thank you all so much for watching. Hope this video helped. We will see you all in the next one.
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