A cannonball leaves the barrel with velocity v = (75î ＋ 45ĵ). At what angle is the barrel tilted above horizontal?

Video transcript

Hey, everyone. So this problem is dealing with vector forces. Let's see what they're asking us. We have a baseball pitcher throwing a ball and a batter strikes it, determine the angle at which the bat is tilted above the horizontal were given the ball's velocity at the instant it leaves the bat in vector form. So that's 15 I and 25 J meters per second. So we're gonna just draw our coordinate system here and We've got 15 I. So that's 15 in the x direction And 25 in the J Direction or the Y Direction. And so our hypotenuse here is going to be what makes the angle. And so this angle theta is what we're looking for in the problem. So when we have, when we're looking for a given angle and we have the adjacent side and the opposite side, we can remember from trig that we are looking at the tangent. So Sokka Tona Tona is what we're after here. So tangent of theta equals opposite over adjacent and so here That equals 25/15. So theta is going to be the inverse tangent of that 25/15. When we plug that in, we get An angle of 59°. So that is our answer for this problem. It aligns with choice C and that's all we have for this one. We'll see you in the next video.