Provide the molecular orbitals of 1,3-butadiene. Cool guys. So the first part should be really easy. All we have to do is fill in the atomic orbitals. So let's go ahead and do that now. How many electrons should be in the atomic orbitals? It should be 4. So it should be 1, 2, 3, 4. Is everyone cool with that? Because we have 2 from each π bond. Perfect. So remember that the number of basically this one's already filled out for you mostly. All you have to do is fill in the phases and that's because we're starting off slow. Typically, you would have to actually draw all these molecular orbitals from scratch, but I'm handing to you half the problem already so that we can practice part of it. Okay?
So what we know by definition is that 4 atomic orbitals should turn into 4 molecular orbitals of increasing energy, right? Cool. We also know that your first atomic, your first molecular orbital should have 0 nodes, meaning there are no places that one that a phase changes. Okay, there are no phase changes happening in my first molecular orbital. That's good. Also guys, I want to just talk a little bit about the nomenclature here. It is common that when we're talking about molecular orbitals of 3 or more that we use the psi symbol to represent each increasing energy state. So the first one would be ψ1, then ψ2, all the way up to ψ4, and it should be up to whatever number of conjugated atoms you have. Now when you're only dealing with 2 conjugated atoms, a lot of times you'll the letter π will be used because π would just be for a pibond, which is 2. So you may see π1, π2 for a double bond, but for anything bigger than a double bond, we use the psi symbol. Cool?
So guys, we know that we have 4 electrons and we need to use the molecular orbital rules to fill in what the other phases should look like. Cool? So right now, how would we know what the phases should look like here? What are the rules that we want to follow? Well, the first rule, well, I mean the first rule was that we have 4 orbitals. Let's go to the next one, which is that your first atomic orbital should not change phases. So that means that, and I keep saying atomic orbital, but I mean the first orbital of your molecular orbital. So that means that I'm going to shade in this one here just like it's shaded down here. Makes sense? And what I'm going to do is I'm also going to shade it in ψ3 and ψ4 because remember that the first rule is that, or remember that the rule for the first orbital is that it doesn't change. Cool? Now what's the rule for the last orbital? The last orbital must always be changing. So let's go ahead and start flipping this one. So that means that over here, it's going to look like this. And then it's going to flip again here. And then it's gonna flip again here. Cool? So everyone's got that? So my first orbital is staying the same, my last orbital keeps flipping. Awesome.
Now we look at nodes and what we say is that your nodes must increase 1 at a time. Right now, I have my nodes is equal to 0 for the first one right. I have 0 nodes, so that means that for ψ2, I should have 1 node. For ψ3, I should have 2 nodes. And for ψ4, I should have 3 nodes. Cool? What I'm going to try to do is figure out symmetrical ways that I can keep these phases the way they are and have one place or or not have one place, but have have these phase changes happening in a symmetrical way. If ψ2 needs to have one node that's symmetrical, where do you think is the best place to put it? Well guys, hopefully what you're saying is that it should be right down the middle because putting it right down the middle would make it symmetrical on both sides. And what that tells us is that if there's only one face change here, that means that this must be flipped up and this one must have stayed down.
Okay. Now notice I'm using the colors blue and black for different reasons. Black means that I already knew that by definition of my rules. Blue means I figured it out based on where the nodes were. Cool? So now I have one node and this is what my ψ2 molecular orbital looks like. So now we know what ψ1 looks like and what ψ2 looks like. Let's see if we can figure out ψ3. So ψ3 needs to have 2 nodes. Where do you think is the best place to put those 2 nodes that it's symmetrical? So I'm hoping that you guys are gonna pick this and this. Okay? Because what that does is it gives me symmetrical nodes that are they're not lopsided make the thing make the thing look symmetrical, okay? So what that means is that my 2 nodes, my 2 orbitals in the middle should look like this, okay? And what this would do is it would allow my phases, my first one and my last one, to follow the rule while also having 2 nodes. Cool.
And lastly guys, what do you think for 3 nodes? How do we do 3 nodes? There's only one way, which is just in between each one. And that means that it's going to be flipping back and forth. So that means that this one is going this way and this one's going this way. Cool? And now we have 3 phase changes and still overall there's symmetry here. Cool? Awesome, guys. So now we have our molecular orbitals filled in and these are the rules we're going to be using throughout any type of of conjugated system. We're going to be using these rules to figure out what our molecular orbitals look like. Okay?
So now all we have to do is we have to use the principles of electron configuration to figure out in which ψ molecular orbitals are those 4 electrons going to reside in. So, for example, I'm going to draw something, please don't draw this, but I'm just going to give you an example. Should I do something like this? Does that make sense where I distribute them evenly throughout all of my ψ orbitals? Please don't do that because what we learned is that the principles of electron configuration applied in molecular orbitals as well. So that means Aufbau principle, build up, always fill your lowest ones first. Pauli Exclusion, you can only have 2 electrons at a time in an orbital. Hund's rule, if you have 2 equal energy level orbitals, fill them symmetrically. What that means is that I should put 2 electrons in ψ1 because that is the lowest energy and I can only fit 2, and then 2 electrons in ψ2 and I'm done. That's it. This is what the linear combination of atomic orbitals diagram or M.O. theory should look like. You should have your molecular orbitals filled in like this and then you should fill in your ψ1 and your ψ2.
I just want to bring up one last thing, which is that I actually have failed to mention what the stars mean. Remember that star is just another description for anti-bonding. So would you assume that this conjugated diene, is it going to be stable or unstable based on how these molecular orbitals are filled? Stable, because right now all I have is bonding orbitals that are filled. Anything basically below the halfway point is bonding. So right now what I have is 2 bonding orbitals that are totally filled. These are going to encourage the atoms to be bonded together. And then I have the anti-bonding orbitals that have no electrons, which is good because you don't want to have electrons in the anti-bonding orbitals. That makes the molecule more unstable, it increases the energy. Cool? Awesome, guys.
So that was that exercise. Let's move on to the next video.