When an α-haloketone reacts with the hydroxide ion, a carboxylic acid is formed. This is known as a Favorskii reaction. Propose a suitable mechanism for the Favorskii reaction below. Hint: The first step is deprotonation of the α-carbon that is not bonded to Br, the second step is forming a three-membered ring, and in the third step HO⁻ acts as a nucleophile.