the-following-cyclic-compound-contains-alternating-single-and-double-bonds-has-1

Question

The compound below contains alternating double bonds and has 14 π electrons (4n + 2 with n = 3), therefore, it is aromatic. Is this statement true or false? Explain.

Accepted Answer

False. The compound is not aromatic because it is not planar, and the π-orbitals will not be lined up.

Answer

True. The compound has all the conditions for it to be aromatic.

Answer

True. The compound is aromatic because all the electrons are delocalized.

Answer

False. Only fully conjugated monocyclic hydrocarbons with less than nine carbons can be aromatic.

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The compound below contains alternating double bonds and has 14 π electrons (4n + 2 with n = 3), therefore, it is aromatic. Is this statement true or false? Explain.